 # The Reaumur temperature scale, while now obscure, was once in common use in some parts of the world. The normal freezing point of water is defined as 0 degrees Reaumur and the normal boiling point of water is defined as 80 degrees Reaumur. Tolstoy’s War and Peace mentions the temperature “minus 20 degrees Reaumur.” What is this in Celsius, Fahrenheit, Kelvin and Rankine? ### Fundamentals of Chemical Engineeri...

1st Edition
Kevin D. Dahm + 1 other
Publisher: Cengage Learning
ISBN: 9781111580704 ### Fundamentals of Chemical Engineeri...

1st Edition
Kevin D. Dahm + 1 other
Publisher: Cengage Learning
ISBN: 9781111580704

#### Solutions

Chapter
Section
Chapter 1.7, Problem 25P
Textbook Problem

## The Reaumur temperature scale, while now obscure, was once in common use in some parts of the world. The normal freezing point of water is defined as 0 degrees Reaumur and the normal boiling point of water is defined as 80 degrees Reaumur. Tolstoy’s War and Peace mentions the temperature “minus 20 degrees Reaumur.” What is this in Celsius, Fahrenheit, Kelvin and Rankine?

Expert Solution
Interpretation Introduction

Interpretation:

Convert the unit of temperature from Reaumur into Celsius, Fahrenheit, Kelvin, and Rankine.

Concept introduction:

Unit conversion for °Re to °C.

T(°C)=[T(°Re)]×54

Here, temperature in degree Celsius and degree Reaumur is T(°C) and T(°Re) respectively.

Unit conversion for °Re to °F.

T(°F)=[T(°Re)×94]+32

Here, temperature in Fahrenheit is T(°F).

Unit conversion for °Re to K.

T(K)=T(°Re)×54+273.15

Here, temperature in kelvin is T(K).

Unit conversion for °Re to °R.

T(K)=T(°Re)×94+491.67

Here, temperature in Rankine is T(°R).

### Explanation of Solution

Given information:

Temperature T=20°Re

Convert the unit of 20°Re in °C.

T(°C)=[T(°Re)]×54        (1)

Substitute 20°Re for T(°Re) in equation (1).

T(°C)=[20°Re]×54=25°C

Thus, the value of temperature in degree Celsius is 25°C_.

Convert the unit of 20°Re in °F.

T(°F)=[T(°Re)×94]+32        (2)

Substitute 20°Re for T(°Re) in equation (2).

T(°F)=[20°Re×94]+32=13°F

Thus, the value of temperature in Fahrenheit is 13°F

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