   Chapter 1.7, Problem 26P Fundamentals of Chemical Engineeri...

1st Edition
Kevin D. Dahm + 1 other
ISBN: 9781111580704

Solutions

Chapter
Section Fundamentals of Chemical Engineeri...

1st Edition
Kevin D. Dahm + 1 other
ISBN: 9781111580704
Textbook Problem

The furlong is a unit of length, equal to one-eighth of a mile, which today is most commonly associated with horse racing. The fathom is a unit of length, equal to six feet, which is most commonly associated with measuring the depth of water.A. The Kentucky Derby is a 10-furlong race. If a horse finishes in exactly two minutes, what is the horse’s average velocity in meters per second? In miles per hour?B. A fishing supply store sells lines that are 20 fathoms long. How many meters is this?C. A treasure chest weighs 100 lbm and is raised to the surface from a depth of 500 fathoms. If gravity is the only force opposing the motion, how much work was required, in Joules?

(A)

Interpretation Introduction

Interpretation:

The horse’s average velocity is to be determined in meters per second and miles per hour.

Concept Introduction:

The average velocity of horse’s in meters per second.

v=dt

Here, distance is d and time is t.

Explanation

Given information:

Distance d=10 furlong.

Time t=2min.

Write the expression to calculate the average velocity of horse’s in meters per second.

v=dt        (1)

Substitute 10 furlong for d and 2 min for t in Equation (1).

v=10furlong2min=10furlong×18milesfurlong2min×(60smin)=1.25miles×5280ftmiles×0.3048mft120s=16

(B)

Interpretation Introduction

Interpretation:

To determine the length of the fishing line in meters.

Concept Introduction:

One fathom is equal to 6 feet.

(C)

Interpretation Introduction

Interpretation:

To determine the work required in Joules.

Concept Introduction:

The work is equal to the multiplication of force and distance.

W=F×d=M×a×d

Here, mass is M, force is F, and distance is d.

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