   Chapter 17, Problem 29P

Chapter
Section
Textbook Problem

At 20.0°C, the carbon resistor in an electric circuit connected to a 5.0-V battery has a resistance of 2.0 × 102 Ω. What is the current in the circuit when the temperature of the carbon rises to 80.0°C?

To determine
The current in the carbon resistor at 80.0°C

Explanation

Given Info: Carbon resistor has resistance 2.0×102Ω at 20.0°C . The voltage of connected battery is 5.0V , Carbon resistor has resistance 2.0×102Ω at 20.0°C . The voltage of connected battery is 5.0V

Explanation:

Formula to calculate resistance at 80.0°C is,

R=R0(1+α(TT0))

• R is the resistance at some temperature T ,
• R0 is the resistance at some reference temperature T0 ,
• α is the temperature coefficient of resistivity of carbon,

Substitute 2.0×102Ω for R0 , 20.0°C for T0 , 80.0°C for T and 0.5×103°C for α in the above equation to find R

R=(2

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