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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

A platinum resistance thermometer has resistances of 200.0 Ω when placed in a 0°C ice bath and 253.8 Ω when immersed in a crucible containing melting potassium. What is the melting point of potassium? Hint: First determine the resistance of the platinum resistance thermometer at room temperature, 20.0°C.

To determine
The melting point of potassium

Explanation

Given Info: Platinum thermometer has resistance 200.0Ω at 0°C and 253.8Ω when immersed in melting potassium, Platinum thermometer has resistance 200.0Ω at 0°C and 253.8Ω when immersed in melting potassium.

Explanation:

Formula to calculate the resistance of platinum thermometer at 20.0°C is,

R0=R(1+α(TT0))

  • R0 is the resistance of platinum thermometer at some reference temperature T0 ,
  • R is the resistance of platinum thermometer at some temperature T ,
  • α is the temperature coefficient of resistivity of platinum,

Take 20.0°C as the reference temperature T0 .

Substitute 200.0Ω for R , 3.92×103(°C)1 for α , 0°C for T , and 20.0°C for T0 in the above equation to find R0 .

R0=200.0Ω(1+(3.92×103°C)(0°C20

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