(a)
Interpretation:
The reaction taking place in two different galvanic cell is given. The sketch of the given galvanic cell along with the cathode and anode and the direction of electron flow, direction of flow of migration of ions through salt bridge, the balanced chemical equation and calculation of
Concept introduction:
The galvanic cell converts chemical energy into electrical energy while the electrolytic cell converts electrical energy into chemical energy.
The species at anode undergoes oxidation while the species at cathode undergoes reduction and the electrons generated at the anode are transferred through wire to the cathode.
To determine: The sketch of the cell given in the chemical equation; the direction of electron flow, identification of the cathode and anode and the migration of ions from salt bridge; the balanced chemical equation for given reaction and the value of overall cell potential.
(b)
Interpretation:
The reaction taking place in two different galvanic cell is given. The sketch of the given galvanic cell along with the cathode and anode and the direction of electron flow, direction of flow of migration of ions through salt bridge, the balanced chemical equation and calculation of
Concept introduction:
The galvanic cell converts chemical energy into electrical energy while the electrolytic cell converts electrical energy into chemical energy.
The species at anode undergoes oxidation while the species at cathode undergoes reduction and the electrons generated at the anode are transferred through wire to the cathode.
To determine: The sketch of the cell given in the chemical equation; the direction of electron flow, identification of the cathode and anode and the migration of ions from salt bridge; the balanced chemical equation for given reaction and the value of overall cell potential.
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Chemistry: An Atoms First Approach
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- Consider a galvanic cell for which the anode reaction is 3 Pb(s)Pb2+(1.0102M)+2e and the cathode reaction is VO2+(0.10M)+2H3O+(0.10M)+eV3+(1.0105M)+3H2O(l) The measured cell potential is 0.640 V. Calculate E for the VO2+V3+ half-reaction, usingE(Pb2+Pb) from Appendix E. Calculate the equilibrium constant (K) at 25°C for thereaction Pb(s)+2VO2+(aq)+4H3O+(aq)Pb2+(aq)+2V3+(aq)+6H2O(l)arrow_forwardThe following two half-reactions arc involved in a voltaic cell. At standard conditions, what species is produced at each electrode? Ag++eAgE=0.80VNi2++2eNiE=0.25Varrow_forward
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