Concept explainers
Write balanced equations and solubility product expressions for the solubility equilibria of the following compounds:
Interpretation:
Thebalanced equation and the solubility product constant of the given compounds are to be calculated.
Concept introduction:
The amount of solute dissolved in a given volume of the solvent to form a saturated solution at a given temperatureis termed as the solubility of the solute in the solvent at that temperature.
The solubility product of a sparingly-soluble salt is given as the product of the concentration of the ions raised to the power equal to the number of times the ion occurs in the equation, after the dissociation of the electrolyte.
The number of moles of the solute dissolved per litre of the solution is called molar solubility.
For a general reaction:
The solubility product can be calculated by the expression as:
Here,
Answer to Problem 45QP
Solution:
Balanced equation:
Solubility product:
Balanced equation:
Solubility product:
Balanced equation:
Solubility product:
Balanced equation:
Solubility product:
Balanced equation:
Solubility product:
Balanced equation:
Solubility product:
Explanation of Solution
a)
The balanced equation for the dissociation of
Let
The initial change equilibrium table for the ionisation of
The equilibrium expression for the reaction is written as follows:
Here,
Substitute the values of
Hence, the solubility product constant of
b)
The balanced equation for the dissociation of
Let
The initial change equilibrium table for the ionisation of
The equilibrium expression for the reaction is written as follows:
Here,
Substitute the values of
Hence, the solubility product constant of
c)
The balanced equation for the dissociation of
Let
The initial change equilibrium table for theionization of
The equilibrium expression for the reaction is written as follows:
Here,
Substitute the values of
Hence, the solubility product constant of
d)
The balanced equation for the dissociation of
Let
The initial change equilibrium table for the ionisation of
The equilibrium expression for the reaction is written as follows:
Here,
Substitute the values of
Hence, the solubility product constant of
e)
The balanced equation for the dissociation of
The ICE table for the ionisation for
Let
The equilibrium expression for the reaction is written as follows:
Here,
Substitute the values of
Hence, the solubility product constant of
f)
The balanced equation for the dissociation of
Let
The initial change equilibrium table for the ionisation of
The equilibrium expression for the reaction is written as follows:
Here,
Substitute the values of
Hence, the solubility product constant of
Want to see more full solutions like this?
Chapter 17 Solutions
Chemistry