Chapter 17, Problem 47E

### Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

Chapter
Section

### Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

# For the reaction C 2 H 2 ( g ) +4F 2 ( g ) → 2CF 4 ( g ) +H 2 ( g ) ∆S° is equal to −358 J/K. Use this value and data from Appendix 4 to calculate the value of S° for CF4(g).

Interpretation Introduction

Interpretation: The reaction between C2H2(g) , F2(g) and the value of ΔS for this reaction is given. The value of S is to be calculated for CF4(g) .

Concept introduction: Entropy (ΔS) is the measure of degree of disorder or randomness.

The expression for ΔS is,

ΔS=npS(product)nfS(reactant)

Explanation

Explanation

The stated reaction is,

C2H2(g)+4F2(g)â†’2CF4(g)+H2(g)

The value of Î”Sâˆ˜ for this reaction is âˆ’358â€‰J/K .

Refer to Appendix 4 .

The value of Sâˆ˜(J/Kâ‹…mol) for the given reactant and product is,

 Molecules Sâˆ˜(J/Kâ‹…mol) C2H2(g) 201 H2(g) 131 F2(g) 203

The formula of Î”Sâˆ˜ is,

Î”Sâˆ˜=âˆ‘npSâˆ˜(product)âˆ’âˆ‘nfSâˆ˜(reactant)

Where,

• Î”Sâˆ˜ is the standard entropy of reaction.
• np is the number of moles of each product.
• nr is the number of moles each reactant.
• Sâˆ˜(product) is the standard entropy of product at a pressure of 1â€‰atm .
• Sâˆ˜(reactant) is the standard entropy of reactant at a pressure of 1â€‰atm .

Substitute all values from the table in the above equation

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started