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Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

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BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

For the reaction

C 2 H 2 ( g ) +4F 2 ( g ) 2CF 4 ( g ) +H 2 ( g )

S° is equal to −358 J/K. Use this value and data from Appendix 4 to calculate the value of S° for CF4(g).

Interpretation Introduction

Interpretation: The reaction between C2H2(g) , F2(g) and the value of ΔS for this reaction is given. The value of S is to be calculated for CF4(g) .

Concept introduction: Entropy (ΔS) is the measure of degree of disorder or randomness.

The expression for ΔS is,

ΔS=npS(product)nfS(reactant)

Explanation

Explanation

The stated reaction is,

C2H2(g)+4F2(g)2CF4(g)+H2(g)

The value of ΔS for this reaction is 358J/K .

Refer to Appendix 4 .

The value of S(J/Kmol) for the given reactant and product is,

Molecules S(J/Kmol)
C2H2(g) 201
H2(g) 131
F2(g) 203

The formula of ΔS is,

ΔS=npS(product)nfS(reactant)

Where,

  • ΔS is the standard entropy of reaction.
  • np is the number of moles of each product.
  • nr is the number of moles each reactant.
  • S(product) is the standard entropy of product at a pressure of 1atm .
  • S(reactant) is the standard entropy of reactant at a pressure of 1atm .

Substitute all values from the table in the above equation

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