
Concept explainers
Epoxide Rearrangements and the NIH Shift
This passage is about two seemingly unrelated aspects of
epoxide rearrangements
arene oxides
These two topics merge in an important biological transformation in which neither the
reactant nor the product is an epoxide
Epoxide rearrangements
In some epoxide ring-opening reactions
As positive charge develops on the ring carbon, one of the groups on the adjacent carbon migrates to it. This migration is assisted by electron
all of this occurs in the same transition state. Subsequent deprotonation gives an
Overall, the reaction resembles the pinacol rearrangement of vicinal
Descriptive Passage and Interpretive Problems) and takes place under similar conditions.
Arene Oxides
Aromatic rings are normally inert to the customary reagents that convert
arene oxides have been synthesized in the laboratory, often by indirect methods. Their chemical
reactivity resembles that of other epoxides.
The most striking thing about arene oxides is their involvement in biological processes. Enzymes
In the liver oxidize
The NIH shift
Although hydroxylation of phenylalanine to tyrosine looks like a typical electrophilic aromatic sub stitution, scientists at the U.S. National Institutes of Health discovered that the biochemical pathway combines epoxidation of the benzene ring followed by epoxide ring opening with rearrangement. This rearrangement, which is the biochemical analog of the pinacol
The hormones serotonin and melatonin are biosynthesized from tryptophan by a series of
reactions, including one that involves an NIH shift.
What is the most likely structure for tryptophan?

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Chapter 17 Solutions
Organic Chemistry - Standalone book
- Identify the missing organic reactants in the following reaction: Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like ) are not shown. In the drawing area below, draw the skeletal ("line") structures of the missing organic reactants and . You may draw the structures in any arrangement that you like, so long as they aren't touching.arrow_forwarde two substances in each sample can interconvert. That is, each kind of molecule can turn into the other. The equilibrium constant K for each interconversion equilibrium is shown below the sketch. Decide whether each solution is at equilibrium. e 8 800 K=3 At equilibrium? yes & 83 K= At equilibrium? no Oyes 32 no G K= 9 K=4 Explanation Check х 80 * B esc 52 F3 FS A C ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center | Accessibility F28 F12arrow_forwardPredict the product of this organic reaction: OH [0] P+ + H₂O Specifically, in the drawing area below draw the skeletal ("line") structure of P. If there isn't any P because this reaction won't happen, check the No reaction box under the drawing area. Note for advanced students: you can assume the reaction is run under mild conditions. Explanation Check Click and drag to start drawing a structure. ப G P x ©2025 McGraw Hill LLC. All Rights Reserved. Termarrow_forward
- Explanation Check Draw the condensed structure of a secondary alcohol with 6 carbon atoms, 1 oxygen atom, and no double or triple bonds. Click anywhere to draw the first atom of your structure. G 2025 McGraw Hill LLC. All Rights Reserved. Term Ć X பarrow_forwardHighlight in red the primary carbons in this molecule. Highlight the quaternary carbons in blue. OH Garrow_forwardDraw the condensed structure of a secondary alcohol with 6 carbon atoms, 1 oxygen atom, and no double or triple bonds. Click anywhere to draw the first atom of your structure. Explanation Check ם' G P x 2025 McGraw Hill LLC. All Rights Reserved. Terms of Usarrow_forward
- What is the missing reactant in this organic reaction? [0] H R + H2O Specifically, in the drawing area below draw the skeletal ("line") structure of R. If there is no reasonable possibility for R, check the No answer box under the drawing area. Click and drag to start drawing a structure. :arrow_forwardIndicate the correct answer:(A) Paper and diamond are polymeric materials.(B) Fiberglass and Teflon are polymeric materials.(C) Teflon and paper are composite materials.(D) Diamond and fiberglass are ceramic materials.arrow_forwardDraw the major product formed in the reaction. Be sure to draw a hydrogen on any heteroatoms, where applicable. NaCN ethanol water Select Draw Templates More Erasearrow_forward
- Predict the major products of the following organic reaction: Some important Notes: Draw the major product, or products, of the reaction in the drawing area below. If there aren't any products, because no reaction will take place, check the box below the drawing area instead. Be sure to draw bonds carefully to show important geometric relationships between substituents. Note: if your answer contains a complicated ring structure, you must use one of the molecular fragment stamps (available in the menu at right) to enter the ring structure. You can add any substituents using the pencil tool in the usual way.arrow_forwardIndicate the correct answer:(A) Paper and diamond are polymeric materials.(B) Fiberglass and Teflon are polymeric materials.(C) Teflon and paper are composite materials.(D) Diamond and fiberglass are ceramic materials.arrow_forwardve two substances in each sample can interconvert. That is, each kind of molecule can turn into the other. The equilibrium constant K for each interconversion equilibrium is shown below the sketch. Decide whether each solution is at equilibrium. 1 க K= 4 At equilibrium? K= At equilibrium? Oyes O no yes no cib 818 814 K=1 K=2 Explanation Check G 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centerarrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning

