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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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BuyFindarrow_forward

Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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. Lead(II) chloride, PbCl2(s), dissolves in water to the extent of approximately 3.6 × 10 2 M at 20 °C. Calculate Kspfor PbCl2(s), and calculate its solubility in grams per liter.

Interpretation Introduction

Interpretation:

The Ksp value and solubility in grams per liter for lead (II) chloride, PbCl2(s) in g/L at 20°C is to be calculated.

Concept Introduction:

The solubility product is represented by Ksp. The solubility product describes the solubility of the solid substance in the solvent at the particular temperature. The term “solubility product” is only used for those substances that are not completely soluble in water.

Explanation

Lead (II) chloride, PbCl2(s) is soluble in water to the extent approximately 3.6×102 at

20°C. The chemical reaction for the solubility of PbCl2(s) is,

PbCl2(s)Pb2+(aq)+2Cl(aq)3.6×1022×3.6×102

The expression for the solubility product ( Ksp ) of lead (II) chloride is given as,

Ksp=[Pb2+][Cl]2=3

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