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Consider a concentration cell similar to the one shown in Exercise 69, except that both electrodes are made of Ni and in the left-hand compartment [Ni 2+ ] = 1.0 M. Calculate the cell potential at 25°C when the concentration of Ni 2+ in the compartment on the right has each of the following values. a. 1.0 M b. 2.0 M c. 0.10 M d. 4.0 × 10 -5 M e. Calculate the potential when both solutions are 2.5 M in Ni 2+ . For each case, also identify the cathode, anode, and the direction in which electrons flow.

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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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Chapter
Section
BuyFindarrow_forward

Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 17, Problem 70E
Textbook Problem
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Consider a concentration cell similar to the one shown in Exercise 69, except that both electrodes are made of Ni and in the left-hand compartment [Ni2+] = 1.0 M. Calculate the cell potential at 25°C when the concentration of Ni2+ in the compartment on the right has each of the following values.

a. 1.0 M

b. 2.0 M

c. 0.10 M

d. 4.0 × 10-5 M

e. Calculate the potential when both solutions are 2.5 M in Ni2+.

For each case, also identify the cathode, anode, and the direction in which electrons flow.

(a)

Interpretation Introduction

Interpretation:

The set up of a concentration cell is given. The value of cell potential at 25°C for different concentration of Ni2+ in the compartment on the right is to be calculated.

Concept introduction:

When the transport of substance occurs from one half cell to another due to difference in concentration gradient there occurs generation of current. This leads to the formation of concentration cells.

They are of two types,

  • Electrode concentration cell
  • Electrolyte concentration cell

The difference in ion concentration in different compartments decides the direction of electron flow and helps in assigning the position of anode and cathode.

To determine: The cell potential at the 1.0M concentration of Ag+ in right compartment and the cathode and anode and the direction of electron flow.

Explanation of Solution

The value of overall cell potential is zero and there occurs no flow of electrons and the position of cathode and anode cannot be specified.

The concentration of Ni2+ in left compartment is 1.0M and in right compartment is also 1.0M . Therefore no flow of electrons will occur and the position of cathode and anode cannot be specified.

The value of Ecell is calculated using Nernst formula,

E=E°(RTnF)ln(Q)

At room temperature the above equation can be specifies as,

E=E°(0.0591n)log(Q)

Where,

  • E  is the cell potential

(b)

Interpretation Introduction

Interpretation:

The set up of a concentration cell is given. The value of cell potential at 25°C for different concentration of Ni2+ in the compartment on the right is to be calculated.

Concept introduction:

When the transport of substance occurs from one half cell to another due to difference in concentration gradient there occurs generation of current. This leads to the formation of concentration cells.

They are of two types,

  • Electrode concentration cell
  • Electrolyte concentration cell

The difference in ion concentration in different compartments decides the direction of electron flow and helps in assigning the position of anode and cathode.

To determine: The cell potential at 2.0M concentration of Ni2+ in right compartment and the cathode and anode and the direction of electron flow.

(c)

Interpretation Introduction

Interpretation:

The set up of a concentration cell is given. The value of cell potential at 25°C for different concentration of Ni2+ in the compartment on the right is to be calculated.

Concept introduction:

When the transport of substance occurs from one half cell to another due to difference in concentration gradient there occurs generation of current. This leads to the formation of concentration cells.

They are of two types,

  • Electrode concentration cell
  • Electrolyte concentration cell

The difference in ion concentration in different compartments decides the direction of electron flow and helps in assigning the position of anode and cathode.

To determine: The cell potential at 0.10M concentration of Ni2+ in right compartment and the cathode and anode and the direction of electron flow.

(d)

Interpretation Introduction

Interpretation:

The set up of a concentration cell is given. The value of cell potential at 25°C for different concentration of Ni2+ in the compartment on the right is to be calculated.

Concept introduction:

When the transport of substance occurs from one half cell to another due to difference in concentration gradient there occurs generation of current. This leads to the formation of concentration cells.

They are of two types,

  • Electrode concentration cell
  • Electrolyte concentration cell

The difference in ion concentration in different compartments decides the direction of electron flow and helps in assigning the position of anode and cathode.

To determine: The cell potential at 4.0×105M concentration of Ni2+ in right compartment and the cathode and anode and the direction of electron flow.

(e)

Interpretation Introduction

Interpretation:

The set up of a concentration cell is given. The value of cell potential at 25°C for different concentration of Ni2+ in the compartment on the right is to be calculated.

Concept introduction:

When the transport of substance occurs from one half cell to another due to difference in concentration gradient there occurs generation of current. This leads to the formation of concentration cells.

They are of two types,

  • Electrode concentration cell
  • Electrolyte concentration cell

The difference in ion concentration in different compartments decides the direction of electron flow and helps in assigning the position of anode and cathode.

To determine: The cell potential when both solutions are 2.5M in Ni2+ .

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Chapter 17 Solutions

Chemistry: An Atoms First Approach
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