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ChemistryIntroductory Chemistry: A Foundation9th Edition

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Chapter 17, Problem 91AP
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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

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Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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. Teeth and bones are composed, to a first approximation, of calcium phosphate. Ca 3 ( PO 4 ) 2 ( s ) . The K for this salt is 1.3 × 10 − 32 at 25 °C. Calculate the concentration of calcium ion in a saturated solution of Ca 3 ( PO 4 ) 2 .

Interpretation Introduction

Interpretation:

The concentration of calcium ion in a saturated solution of Ca3(PO4)2 is to be calculated.

Concept Introduction:

The solubility product is represented by Ksp. The solubility product describes the solubility of the solid substance in the solvent at the particular temperature. The high value of solubility product indicates that the substance will be more soluble in water, whereas the low value of solubility product is the indication of the low solubility of the solid in the solvent.

Explanation

The given substance is Ca3(PO4)2. On dissolution in water, salts dissociate to form metallic cations and hydroxide anions. The ionization reaction of Ca3(PO4)2 is,

Ca3(PO4)2(s)⇌3Ca2+(aq)+2PO43−(aq)

The solubility of the salt is assumed to be s mol/L to reach equilibrium.

Therefore, at equilibrium, [Ca2+]=3s mol/L and [PO43−]=3s mol/L

According to the law of chemical equilibrium, the solubility product for Ca3(PO4)2 is,

Ksp=[Ca2+]3[PO43−]2=(3s)3×(2s)2=27s3×4s2

The solubility product, Ksp for Ca3(PO4)2 is 1

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