   # Calculate the solubility of AgCN in moles per liter and grams per liter. K sp for AgCN is 6.0 × 10 −17 . ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 17.4, Problem 2CYU
Textbook Problem
93 views

## Calculate the solubility of AgCN in moles per liter and grams per liter. Ksp for AgCN is 6.0 × 10−17.

Interpretation Introduction

Interpretation:

Solubility of saltAgCNhas to be calculated in molL1and gL1units using Ksp value.

Concept introduction:

The solubility of a salt is defined as the maximum amount of salt that can be dissolved in definite amount of solvent. It is expressed in moles per liter or grams per liter. Solubility in terms of moles per liter is called molar solubility and is defined as the number of moles of solute (salt) dissolved in per liter of solution.

Solubility product constant Ksp is an equilibrium constant and is defined as the product of the equilibrium concentration of the ions of the salt raised to the power of their coefficients in the balanced chemical equation.

The expression for Ksp of a salt is given as,

AxBysxAy+aq+yBxaqKsp=Ay+xBxy

The relation between Ksp andsis derived as follows:

EquationAxByxAy++yBxInitialM00ChangeM+xs+ysEquilibriumMxsys

Ksp=Ay+xBxyKsp=xsxysy=xxyysx+ysx+y=Kspxxyy=Kspxxyy1/x+y

Here,

• xis the coefficient of cation A+y
• yis the coefficient of anion Bx
• sis the molar solubility

Ksp is calculated by using molar solubility of the salt.

### Explanation of Solution

The balanced chemical reaction involved  is,

AgCNs Ag+1aq+ CN1aq

The ICE table is as follows,

EquationAgCNAg+1+CN1Initial M00Change M+s+sEquilibrium M ss

The value of solubility product Kspof AgCN is6.0×1017,

Ksp=Ag+1CN1

Substitute s for Ca2+ and forCN1.

Ksp=s×s

Here,

• Ksp is solubility product constant
• s is solubility

Ksp=s2

Rearrange the above expression.

s=Ksp2

Again, substitute 6.0×1017forKsp.

s=6.0×10172= 7

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