   Chapter 17.6, Problem 1.2ACP

Chapter
Section
Textbook Problem

What is the minimum volume of 0.0071 M NaCN(aq) necessary to dissolve the gold from 1.0 metric ton (1000 kg) of ore if the ore contains 0.012% gold?

Interpretation Introduction

Interpretation:

Minimum volume of 0.0071 M NaCN necessary to dissolve the gold from 1.0 metric ton of ore has to be calculated if the ore contains 0.012 % gold.

Concept introduction:

Gold is extracted from the gold bearing ore through a chemical process involving dissolution of gold ore in aqueous NaCN solution. The reaction involved is given as,

4 Au(s)+8 NaCN(aq)+O2(g)+2H2O(l)4NaAu(CN)2(aq)+4NaOH(aq)

The solution containing gold cyanide complex is then filtered to separate it from solids and then reacted with zinc to obtain pure metallic gold.

Explanation

Minimum volume of 0.0071 M NaCN necessary to dissolve the gold from 1.0 metric ton of ore is calculated below.

Given:

Mass of ore is 1000 Kg.

Molarity of NaCN solution is 0.0071 M.

Percent of gold in ore is 0.012 %.

% gold=(mass of goldmass of ore)100mass of gold=(% gold)(mass of ore)100

Substitute the values and calculate the mass of gold present in the ore.

mass of gold=(0.012)(1000 Kg)(1000 g1 Kg)100=0.012×104 g

Molar mass of gold is 197 g.

Number of moles of gold is,

n= (0.012×104 g)197 gmol1=0

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