Chapter 17.6, Problem 1.2ACP

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# What is the minimum volume of 0.0071 M NaCN(aq) necessary to dissolve the gold from 1.0 metric ton (1000 kg) of ore if the ore contains 0.012% gold?

Interpretation Introduction

Interpretation:

Minimum volume of 0.0071 M NaCN necessary to dissolve the gold from 1.0 metric ton of ore has to be calculated if the ore contains 0.012 % gold.

Concept introduction:

Gold is extracted from the gold bearing ore through a chemical process involving dissolution of gold ore in aqueous NaCN solution. The reaction involved is given as,

4 Au(s)+8 NaCN(aq)+O2(g)+2H2O(l)4NaAu(CN)2(aq)+4NaOH(aq)

The solution containing gold cyanide complex is then filtered to separate it from solids and then reacted with zinc to obtain pure metallic gold.

Explanation

Minimum volume of 0.0071Â M NaCN necessary to dissolve the gold from 1.0Â metricÂ ton of ore is calculated below.

Given:

Mass of ore is 1000â€‹â€‹Â Kg.

Molarity of NaCN solution is 0.0071Â M.

Percent of gold in ore is 0.012â€‹Â %.

%Â gold=(massÂ ofÂ goldmassÂ ofÂ ore)100massÂ ofÂ gold=(%Â gold)(massÂ ofÂ ore)100

Substitute the values and calculate the mass of gold present in the ore.

massÂ ofÂ gold=(0.012)(1000Â Kg)(1000Â g1Â Kg)100=0.012Ã—104Â g

Molar mass of gold is 197Â g.

Number of moles of gold is,

n=Â (0.012Ã—104Â g)197Â gâ‹…molâˆ’1=0

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