   Chapter 17.6, Problem 17.9QQ

Chapter
Section
Textbook Problem

Two resistors, A and B, are connected in a series circuit with a battery. The resistance of A is twice that of B. Which resistor dissipates more power? (a) Resistor A does. (b) Resistor B does. (c) More information is needed.

To determine
The resistor which dissipates more power.

Explanation

Given Info: Two resistors, A and B, are connected in series circuit with a battery. The resistance of A is twice that of B.

Explanation:

Formula to calculate the power is,

PB=I2RB

• PB is the power dissipated in resistor B,
• I is the current through the resistors,
• RB is the resistance of resistor B,

Power dissipated in resistor A is,

PA=I2RA

• PA is the power dissipated in resistor A,
• I is the current through the resistors,
• RA is the resistance of resistor A,

Resistance of A is twice that of B RA=2RB

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts 