   # What is the minimum volume of 0.0071 M NaCN(aq) necessary to dissolve the gold from 1.0 metric ton (1000 kg) of ore if the ore contains 0.012% gold? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 17.7, Problem 2Q
Textbook Problem
3 views

## What is the minimum volume of 0.0071 M NaCN(aq) necessary to dissolve the gold from 1.0 metric ton (1000 kg) of ore if the ore contains 0.012% gold?

Interpretation Introduction

Interpretation:

Minimum volume of 0.0071 MNaCN necessary to dissolve the gold from 1.0 metric tonof ore has to be calculated if the ore contains 0.012 % gold.

Concept introduction:

Gold is extracted from the gold bearing ore through a chemical process involving dissolution of gold ore in aqueous NaCN solution. The reaction involved is given as,

4 Aus+8 NaCNaq+O2g+2H2Ol4NaAuCN2aq+4NaOHaq

The solution containing gold cyanide complex is then filtered to separate it from solids and then reacted with zinc to obtain pure metallic gold.

### Explanation of Solution

Given data is as follows:

Mass of ore is 1000 Kg.

Molarity of NaCN solution is 0.0071 M.

Percent of gold in ore is 0.012 %.

Equation to calculate mass percent is given below:

% gold=mass of goldmass of ore100mass of gold=% goldmass of ore100

Substitute the values and calculate the mass of gold present in the ore.

mass of gold=0.0121000 Kg1000 g1 Kg100=0.012×104 g

Molar mass of gold is197 g.

Number of moles of gold is,

n= 0.012×104 g197 gmol1=0.609 mol

From the reaction, moles of NaCN required for 0

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