# Theequation of a circle from the figure provided below,

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.8, Problem 102E
To determine

## To calculate: Theequation of a circle from the figure provided below,

Expert Solution

Theequation of the circle is (x+1)2+(y1)2=10 .

### Explanation of Solution

Given information:

The graph of the circle is provided below,

Formula used:

The standard form of the equation of the circle is (xh)2+(yk)2=r2 , where (h,k) denote the center of the circle and r denote the radius.

Distance d(A,B) between two points A=(x1,y1) and B=(x2,y2) in the Cartesian plane is denoted by d(A,B)=(x2x1)2+(y2y1)2 .

Calculation:

Consider the provided graph of the circle,

It is observed that center of the circle is at (1,1) .

Since the circle passes through the point (2,0) , and center is at (1,1) therefore radius of circle is the distance between the points (2,0) and (1,1) .

Recall that the distance d(A,B) between two points A=(x1,y1) and B=(x2,y2) in the Cartesian plane is denoted by d(A,B)=(x2x1)2+(y2y1)2 .

Apply it,

d(A,B)=(12)2+(10)2=(3)2+(1)2=9+1=10

Recall that the standard form of the equation of the circle is (xh)2+(yk)2=r2 , where (h,k) denote the center of the circle and r denote the radius.

Compare, (h,k) and (1,1) also radius ris 10 .

Here, h=1,k=1 and r=10 .

Substitute the values in standard equation of circle,

(x(1))2+(y1)2=(10)2(x+1)2+(y1)2=10

Thus, the equation of circle is (x+1)2+(y1)2=10 .

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