BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.8, Problem 115E

(a)

To determine

The closest and the farthest points that the satellite gets to the center of the moon in the graph.

Expert Solution

Answer to Problem 115E

The closest and the farthest points that the satellite gets to the center of the moon in the graph is (2,0) and (8,0) respectively.

Explanation of Solution

Given:

The equation of satellite’s orbit is,

(x3)225+y216=1

And the graph of orbit with the centre of the moon at the origin is,

Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.8, Problem 115E , additional homework tip  1

Figure (1)

Calculation:

The closest and farthest points in satellite’s orbit can be found by the intersection points of equation (x3)225+y216=1 and y=0 (x-axis),

Substitute 0 for y in orbit equation (x3)225+y216=1 for the x,

(x3)225+0216=1(x3)225=1(x3)2=25x3=25

Further solve,

x3=25x=(±5+3)x=8,2

So the closest and the farthest points that the satellite gets to the center of the moon in the graph is (2,0) and (8,0) respectively.

(b)

To determine

The x-coordinates of points in the orbit with y-coordinates 2 and find their distances to the center of moon.

Expert Solution

Answer to Problem 115E

The x-coordinates of points in the orbit with y-coordinates 2 is 7.3303 and (1.3303) . and distance of the point (7.3303,2) with the center of moon (0,0) is 7.60megameters and distance of the point (1.3303,2) with the center of moon (0,0) is 2.40megameters.

Explanation of Solution

Given:

The equation of satellite’s orbit is,

(x3)225+y216=1

And the graph of orbit with the centre of the moon at the origin is,

Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.8, Problem 115E , additional homework tip  2

Figure (1)

Calculation:

The x-coordinates of the points in the orbit with y-coordinates 2 is,

(x3)225+2216=1(x3)225+416=1(x3)225=114(x3)225=34

Further solve,

(x3)225=34(x3)2=34×25x3=754x=(±532+3)

So the two value of x is (532+3)=7.3303 and (532+3)=(1.3303) .

And the distance of the point (7.3303,2) with the center of moon (0,0) is,

(7.33030)2+(20)2=53.73+4=57.73=7.60

So distance of the point (7.3303,2) with the center of moon (0,0) is 7.60megameters.

And the distance of the point (1.3303,2) with the center of moon (0,0) is,

(1.33030)2+(20)2=1.77+4=5.77=2.40

So distance of the point (1.3303,2) with the center of moon (0,0) is 2.40megameters.

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