Chapter 18, Problem 11P

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Chapter
Section

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# Consider the circuit shown in Figure P18.11. Find (a) the potential difference between points a and b and (b) the current in the 20.0-Ω resistor.Figure P18.11

(a)

To determine
The potential difference between the points a and b.

Explanation

Given Info: The bottom of the two resistors connected in series combinations are 20.0â€‰Î© and 5.00â€‰Î© . The other resistors connected in parallel combinations are 25.0â€‰Î© , 10.0â€‰Î© and 5.00â€‰Î© . The potential difference across the battery is 25.0 V and from the step 3 two resistors is 2.94â€‰Î© and 10.0â€‰Î© .

Explanation:

Formula to calculate the equivalent resistance of the two resistors connected in series.

Rs=R4+R5

• Rs is the equivalent resistance of the two resistors connected in series,
• R4 and R5 is the resistors,

Thus, the equivalent resistance of the two resistors connected in series is 25.0â€‰Î© .

Formula to calculate the equivalent resistance of the resistors connected in parallel.

1Rp=1R2+1R3+1Rs

• Rs is the equivalent resistance of the two resistors connected in series,
• R2 and R3 is the resistors,
• Rp is the equivalent resistance of the resistors connected in parallel,

1Rp=110

(b)

To determine
The current passing through the 20.0Ω resistor.

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