Chapter 18, Problem 15P

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Chapter
Section

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# Find the current in the 12-Ω resistor in Figure P18.15.Figure P18.15

To determine
The current passing through the 12.0Ω resistor from the figure 1.

Explanation

Explanation:

The resistors in the circuit can be combined in the stages shown below:

Formula to calculate the equivalent resistance of the two resistors connected in parallel combination is,

1Rp1=1R6+1R6

• Rp1 is the equivalent resistance of the two resistors connected in parallel,
• R6 is the resistor,

Substitute 6.0â€‰Î© for R6 to find Rp1 .

Thus, the equivalent resistance of the two resistors connected in parallel is Rp1=3.0â€‰Î© .

Formula to calculate the equivalent resistance of the two resistors connected in second parallel combination is,

1Rp2=1R4+1R12

• Rp2 is the equivalent resistance of the two resistors connected in second parallel,
• R4 and R12 is the resistors,

Substitute 4.0â€‰Î© for R4 and 12.0â€‰Î© for R12 to find Rp2 .

Thus, the equivalent resistance of the two resistors connected in second parallel is Rp2=3.0â€‰Î© .

Formula to calculate the equivalent resistance of the two resistors connected in first series combination is,

Rs1=R3+R3

• Rs1 is the equivalent resistance of the two resistors connected in series,
• R3 is the resistor,

Substitute 3.0â€‰Î© for R3 to find Rs1 .

Thus, the equivalent resistance of the two resistors connected in series is Rs1=6.0â€‰Î© .

Formula to calculate the equivalent resistance of the two resistors connected in second series combination is,

Rs2=R3+R2

• Rs2 is the equivalent resistance of the two resistors connected in second series combination,
• R3 and R2 is the resistors,

Substitute 3.0â€‰Î© for R3 and 2.0â€‰Î© for R2 to find Rs2 .

Thus, the equivalent resistance of the two resistors connected in second series is Rs2=5.0â€‰Î© .

Formula to calculate the equivalent resistance of the two resistors connected in parallel combination is,

1Rp=1R6+1R5

• Rp is the equivalent resistance connected in parallel,
• R6 and R5 is the resistors,

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started