Concept explainers
Calculate the Euler buckling load for an axially loaded, pin-connected
The Euler buckling load for the given member.
Answer to Problem 18.1P
Explanation of Solution
Given:
Column length is
For structural steel modulus of elasticity is
Calculation:
For the wide flange section
Least moment of inertia of the cross section is
The Euler’s buckling for axially loaded member can be
Conclusion:
Therefore, the Euler’s buckling for axially loaded member is,
Want to see more full solutions like this?
Chapter 18 Solutions
Applied Statics and Strength of Materials (6th Edition)
Additional Engineering Textbook Solutions
Engineering Mechanics: Statics
Engineering Mechanics: Statics & Dynamics (14th Edition)
Statics and Mechanics of Materials (5th Edition)
Manufacturing Engineering & Technology
Automotive Technology: Principles, Diagnosis, and Service (5th Edition)
Engineering Mechanics: Dynamics (14th Edition)
- (a) Explain FIVE (5) factors that may influence the optimum column design under an axial compressive load. (b) A 3.6 m long pin-ended column is formed from an A-36 steel circular hollow section with an outer diameter of 75 mm. Determine the minimum thickness, t (to the nearest integer in mm) of the circular hollow section so that the column can safely support the load of 200 kN without buckling. If the outer diameter of the steel circular hollow section is reduced to 62 mm and the ends are pinned-fixed supported, analyse whether the column with the same applied load and the sectional thickness computed above will cause a buckling failure.arrow_forwardA mild steel tie-rod has to carry an axial load of 60KN. The maximum permissible stress is 200N/mm2. Calculate a suitable diameter for the rod.arrow_forwardFor a solid cylindrical steel structure with length of 1.5 meters that is expected to withstand a buckling load of 200 kN, calculate its diameter based on the Euler formula for the cases of pinned-pinned, pinned-fixed and fixed-fixed ends.arrow_forward
- Determine the critical axial buckling load for an 8 3/4 x 12 inches glue-laminated column braced at 10ft from the bottom in the y axis for a total height of 25ft. Assume pin connections at top and bottom. Fc= 1750 psi, E= 1.8x106 psi. (Western cross-section glu-lam data is in the text).arrow_forwardDetermine the critical buckling load for a column that is pin supported?arrow_forwardDetermine the load in member BC of figure below.arrow_forward
- A steel bar carries the axial loads at the positions shown. If E=200GPa, compute the maximumload P if the total deformation of the bar is not to exceed 5mm. Assume that the bar is suitablebraced to prevent buckling.arrow_forwardCompute the internal diameter of the 10 m length hollow cast iron column. If the externaldiameter is two times the internal diameter and the safe compressive load on a hollowcast iron column with one end rigidly fixed and other end hinged is 60 kN. Use Euler’sformula with a factor of safety of 3 and E = 90 kN/mm2arrow_forwardA column consists of a 2.5 m long hollow tube with an outside diameter equal to 1.5 times that of the inside diameter. The column must carry an axial load of 40 KN without buckling. Use a factor of safety of 5 and calculate the dimensions of the tube if one end is fixed and the other end is free. Use the Euler formula and take ?=200 ???.arrow_forward
- Determine the ratio of buckling strengths of two columns of circular cross-section, one hollow and other solid when both are made of same material, have same length, cross-sectional area and end conditions. The internal diameter of the hollow column is half of its external diameter.arrow_forwardGiven a 5.7meter Channel steel compression member (C7x12.25) with Fy = 345MPa. Calculate the design strength in KN that the channel section can carry.a. Case 1: If both ends are hinged,b. Case 2: If both ends are built-in or fixed,Note: Always check SR≤200 otherwise provide lateral support at mid-heightarrow_forwardVerify the adequacy of column AB, part of a sway frame structure, to carry the loads shown in the figure. The column is made of ASTM A992 steel (Fy = 50 ksi). Use ASD specifications. For determining its effective length factors, neglect inelastic effect.arrow_forward
- Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning