ORGANIC CHEMISTRY W/CONNECT PKG
ORGANIC CHEMISTRY W/CONNECT PKG
5th Edition
ISBN: 9781260901269
Author: SMITH
Publisher: MCG CUSTOM
Question
Chapter 18, Problem 18.1P
Interpretation Introduction

Interpretation: The reason corresponding to the fact that the benzene is less reactive toward electrophiles than an alkene, even though it has more π electrons than an alkene is to be stated.

Concept introduction: Benzene is an aromatic compound. It has electrons. It is a stable compound due to the resonance. The molecular formula of benzene is C6H6.

Expert Solution & Answer
Check Mark

Answer to Problem 18.1P

The benzene is less reactive toward electrophiles than an alkene because of its stability and aromaticity.

Explanation of Solution

Benzene is an aromatic compound. A non-aromatic compound is formed by the addition reaction of benzene. It gives an unstable product. Benzene undergoes substitution reaction because the aromaticity of benzene does not get affected. Hence, benzene is less reactive toward electrophiles than an alkene because of its stability and aromaticity.

Conclusion

The benzene is less reactive toward electrophiles than an alkene because of its stability and aromaticity.

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Chapter 18 Solutions

ORGANIC CHEMISTRY W/CONNECT PKG

Ch. 18 - Prob. 18.11PCh. 18 - Prob. 18.12PCh. 18 - Prob. 18.13PCh. 18 - Problem 18.14 Draw all resonance structures for...Ch. 18 - Problem 18.15 Classify each substituent as...Ch. 18 - Prob. 18.16PCh. 18 - Problem 18.17 Label each compound as more or less...Ch. 18 - Problem 18.18 Rank the following compounds in...Ch. 18 - Prob. 18.19PCh. 18 - Problem 18.20 Draw the products of each...Ch. 18 - Prob. 18.21PCh. 18 - Problem 18.22 Draw the products formed when each...Ch. 18 - Problem 18.23 Devise a synthesis of each compound...Ch. 18 - Problem 18.24 Draw the products of each...Ch. 18 - Problem 18.25 Draw a stepwise mechanism for the...Ch. 18 - Problem 18.26 Draw the products of each...Ch. 18 - Prob. 18.27PCh. 18 - Prob. 18.28PCh. 18 - Problem 18.29 How could you use ethylbenzene to...Ch. 18 - Prob. 18.30PCh. 18 - Problem 18.31 What steps are needed to convert...Ch. 18 - Problem 18.32 Synthesize each compound from...Ch. 18 - Problem 18.33 Synthesize each compound from...Ch. 18 - Prob. 18.34PCh. 18 - 18.35 What is the major product formed by an...Ch. 18 - 18.36 Draw the products formed when phenol is...Ch. 18 - Problem 18.37 Draw the products formed when each...Ch. 18 - 18.38 Draw the products of each reaction. a. d....Ch. 18 - 18.39 What products are formed when benzene is...Ch. 18 - 18.40 Draw the products of each reaction. c. d....Ch. 18 - 18.41 You have learned two ways to make an alkyl...Ch. 18 - 18.42 Draw the structure of A, an intermediate in...Ch. 18 - Prob. 18.43PCh. 18 - Prob. 18.44PCh. 18 - 18.45 Explain why each of the following reactions...Ch. 18 - Prob. 18.46PCh. 18 - 18.47 For each of the following substituted...Ch. 18 - 18.48 Consider the tetracyclic aromatic compound...Ch. 18 - 18.49 For each N-substituted benzene, predict...Ch. 18 - Prob. 18.50PCh. 18 - 18.51 Using resonance structures, explain why a...Ch. 18 - Prob. 18.52PCh. 18 - 18.53 Rank the aryl halides in each group in order...Ch. 18 - 18.54 Draw a stepwise mechanism for the following...Ch. 18 - Prob. 18.55PCh. 18 - 18.56 Draw a stepwise, detailed mechanism for the...Ch. 18 - Prob. 18.57PCh. 18 - 18.58 Draw a stepwise mechanism for the following...Ch. 18 - Prob. 18.59PCh. 18 - Prob. 18.60PCh. 18 - Prob. 18.61PCh. 18 - Prob. 18.62PCh. 18 - 18.63 Synthesize each compound from benzene and...Ch. 18 - Problem 18.64 Synthesize each compound from...Ch. 18 - Prob. 18.65PCh. 18 - Prob. 18.66PCh. 18 - Prob. 18.67PCh. 18 - Prob. 18.68PCh. 18 - Problem 18.69 Identify the structures of isomers A...Ch. 18 - Prob. 18.70PCh. 18 - Problem 18.71 Compound X (molecular formula ) was...Ch. 18 - 18.72 Reaction of p-cresol with two equivalents of...Ch. 18 - Prob. 18.73PCh. 18 - The NMR spectrum of phenol () shows three...Ch. 18 - Explain the reactivity and orientation effects...Ch. 18 - Prob. 18.76PCh. 18 - Prob. 18.77PCh. 18 - Prob. 18.78PCh. 18 - Prob. 18.79P
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