Physics for Scientists and Engineers, Technology Update (No access codes included)
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN: 9781305116399
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 18, Problem 18.2P

Two wave pulses A and B are moving in opposite directions, each with a speed v = 2.00 cm/s. The amplitude of A is twice the amplitude of B. The pulses are shown in Figure P17.3 at t = 0. Sketch the resultant wave at t = 1.00 s, 1.50 s, 2.00 s, 2.50 s, and 3.00 s.

Figure P17.3

Chapter 18, Problem 18.2P, Two wave pulses A and B are moving in opposite directions, each with a speed v = 2.00 cm/s. The

Expert Solution & Answer
Check Mark
To determine

To sketch: The graph of the resultant wave at different time period.

Explanation of Solution

Introduction: Wave is a disturbance that transfers the energy from one place two other through a matter and the amplitude denotes the intensity of the wave.

Section 1:

To sketch: The graph of the resultant wave at time t=1s .

Introduction: Wave is a disturbance that transfers the energy from one place two other through a matter and the amplitude denotes the intensity of the wave.

Explanation:

Given information: The speed of the waves A and B is 2cm/s and the amplitude of the wave A is twice than the amplitude of the wave B .

The given Figure of the pluses is shown below.

Physics for Scientists and Engineers, Technology Update (No access codes included), Chapter 18, Problem 18.2P , additional homework tip  1

Figure (I)

Formula to calculate distance is,

d=vt

  • d is the distance
  • v is the speed of the wave.
  • t is the time travel of two in opposite direction to each other.

Substitute 2cm/s for v and 1s for t .

d=(2cm/s)(1s)=2cm

The two waves A and B will move towards each other by the distance of 2cm along x axis.

Thus, the graph of the resultant wave at t=1s is shown below.

Physics for Scientists and Engineers, Technology Update (No access codes included), Chapter 18, Problem 18.2P , additional homework tip  2

Figure (II)

Conclusion:

Therefore, the graph of the resultant wave at time t=1s is shown in Figure (II).

Section 2:

To sketch: The graph of the resultant wave at time t=1.5s .

Introduction: Wave is a disturbance that transfers the energy from one place two other through a matter and the amplitude denotes the intensity of the wave.

Explanation:

Given information: The speed of the waves A and B is 2cm/s and the amplitude of the wave A is twice than the intensity of the wave B .

At t=1.5s ,

Formula to calculate distance at  is,

d=vt

  • d is the distance
  • v is the speed of the wave.
  • t is the time travel of two in opposite direction to each other.

Substitute 2cm/s for v and 1.5s for t .

d=(2cm/s)(1.5s)=3cm

The two waves A and B will move towards each by 3cm along x axis.

Thus, the graph of the resultant wave at t=1.5s is shown below.

Physics for Scientists and Engineers, Technology Update (No access codes included), Chapter 18, Problem 18.2P , additional homework tip  3

Figure (III)

Conclusion:

Therefore, the graph of the resultant wave is at time t=1.5s is shown in Figure (III).

Section 3:

To sketch: The graph of the resultant wave at time t=2s .

Introduction: Wave is a disturbance that transfers the energy from one place two other through a matter and the amplitude denotes the intensity of the wave.

Explanation:

Given information: The speed of the waves A and B is 2cm/s and the amplitude of the wave A is twice than the intensity of the wave B .

Formula to calculate distance at  is,

d=vt

  • d is the distance
  • v is the speed of the wave.
  • t is the time travel of two in opposite direction to each other.

Substitute 2cm/s for v and 2s for t .

d=(2cm/s)(2s)=4cm

The two waves A and B will move towards each by 4cm along x axis.

Thus, the graph of the resultant wave at t=2s is shown below.

Physics for Scientists and Engineers, Technology Update (No access codes included), Chapter 18, Problem 18.2P , additional homework tip  4

Figure (IV)

Conclusion:

Therefore, the graph of the resultant wave at time t=2s is shown in Figure (IV).

Section 4:

To sketch: The graph of the resultant wave at time t=2.5s .

Introduction: Wave is a disturbance that transfers the energy from one place two other through a matter and the amplitude denotes the intensity of the wave.

Explanation:

Given information: The speed of the waves A and B is 2cm/s and the amplitude of the wave A is twice than the intensity of the wave B .

Formula to calculate distance at  is,

d=vt

  • d is the distance
  • v is the speed of the wave.
  • t is the time travel of two in opposite direction to each other.

Substitute 2cm/s for v and 2.5s for t .

d=(2cm/s)(2.5s)=5cm

The two waves A and B will move towards each by 5cm along x axis.

Thus, the graph of the resultant wave at t=2.5s is shown below.

Physics for Scientists and Engineers, Technology Update (No access codes included), Chapter 18, Problem 18.2P , additional homework tip  5

Figure (V)

Conclusion:

Therefore, the graph of the resultant wave is at time t=2.5s is shown in Figure (V).

Section 5:

To sketch: The graph of the resultant wave at time t=3s .

Introduction: Wave is a disturbance that transfers the energy from one place two other through a matter and the amplitude denotes the intensity of the wave.

Explanation:

Given information: The speed of the waves A and B is 2cm/s and the amplitude of the wave A is twice than the intensity of the wave B .

Formula to calculate distance at  is,

d=vt

  • d is the distance
  • v is the speed of the wave.
  • t is the time travel of two in opposite direction to each other.

Substitute 2cm/s for v and 3s for t .

d=(2cm/s)(3s)=6cm

The two waves A and B will move towards each by 6cm along x axis.

Thus, the graph of the resultant wave at t=3s is shown below.

Physics for Scientists and Engineers, Technology Update (No access codes included), Chapter 18, Problem 18.2P , additional homework tip  6

Figure (VI)

Conclusion:

Therefore, the graph of the resultant wave is at time t=3s is shown in Figure (VI).

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Chapter 18 Solutions

Physics for Scientists and Engineers, Technology Update (No access codes included)

Ch. 18 - When two tuning forks are sounded at the same...Ch. 18 - A tuning fork is known to vibrate with frequency...Ch. 18 - An archer shoots an arrow horizontally from the...Ch. 18 - As oppositely moving pulses of the same shape (one...Ch. 18 - Prob. 18.10OQCh. 18 - Suppose all six equal-length strings of an...Ch. 18 - Assume two identical sinusoidal waves are moving...Ch. 18 - Prob. 18.1CQCh. 18 - When two waves interfere constructively or...Ch. 18 - Prob. 18.3CQCh. 18 - What limits the amplitude of motion of a real...Ch. 18 - Prob. 18.5CQCh. 18 - An airplane mechanic notices that the sound from a...Ch. 18 - Despite a reasonably steady hand, a person often...Ch. 18 - Prob. 18.8CQCh. 18 - Does the phenomenon of wave interference apply...Ch. 18 - Two waves are traveling in the same direction...Ch. 18 - Two wave pulses A and B are moving in opposite...Ch. 18 - Two waves on one string are described by the wave...Ch. 18 - Two pulses of different amplitudes approach each...Ch. 18 - A tuning fork generates sound waves with a...Ch. 18 - The acoustical system shown in Figure OQ18.1 is...Ch. 18 - Two pulses traveling on the same string are...Ch. 18 - Two identical loudspeakers are placed on a wall...Ch. 18 - Two traveling sinusoidal waves are described by...Ch. 18 - Why is the following situation impossible? Two...Ch. 18 - Two sinusoidal waves on a string are defined by...Ch. 18 - Two identical sinusoidal waves with wavelengths of...Ch. 18 - Two identical loudspeakers 10.0 m apart are driven...Ch. 18 - Prob. 18.14PCh. 18 - Two sinusoidal waves traveling in opposite...Ch. 18 - Verify by direct substitution that the wave...Ch. 18 - Two transverse sinusoidal waves combining in a...Ch. 18 - A standing wave is described by the wave function...Ch. 18 - Two identical loudspeakers are driven in phase by...Ch. 18 - Prob. 18.20PCh. 18 - A string with a mass m = 8.00 g and a length L =...Ch. 18 - The 64.0-cm-long string of a guitar has a...Ch. 18 - The A string on a cello vibrates in its first...Ch. 18 - A taut string has a length of 2.60 m and is fixed...Ch. 18 - A certain vibrating string on a piano has a length...Ch. 18 - A string that is 30.0 cm long and has a mass per...Ch. 18 - In the arrangement shown in Figure P18.27, an...Ch. 18 - In the arrangement shown in Figure P17.14, an...Ch. 18 - Review. A sphere of mass M = 1.00 kg is supported...Ch. 18 - Review. A sphere of mass M is supported by a...Ch. 18 - Prob. 18.31PCh. 18 - Review. A solid copper object hangs at the bottom...Ch. 18 - Prob. 18.33PCh. 18 - The Bay of Fundy, Nova Scotia, has the highest...Ch. 18 - An earthquake can produce a seiche in a lake in...Ch. 18 - High-frequency sound can be used to produce...Ch. 18 - Prob. 18.37PCh. 18 - Prob. 18.38PCh. 18 - Calculate the length of a pipe that has a...Ch. 18 - The overall length of a piccolo is 32.0 cm. The...Ch. 18 - The fundamental frequency of an open organ pipe...Ch. 18 - Prob. 18.42PCh. 18 - An air column in a glass tube is open at one end...Ch. 18 - Prob. 18.44PCh. 18 - Prob. 18.45PCh. 18 - A shower stall has dimensions 86.0 cm 86.0 cm ...Ch. 18 - Prob. 18.47PCh. 18 - Prob. 18.48PCh. 18 - As shown in Figure P17.27, water is pumped into a...Ch. 18 - As shown in Figure P17.27, water is pumped into a...Ch. 18 - Two adjacent natural frequencies of an organ pipe...Ch. 18 - Why is the following situation impossible? A...Ch. 18 - A student uses an audio oscillator of adjustable...Ch. 18 - An aluminum rod is clamped one-fourth of the way...Ch. 18 - Prob. 18.55PCh. 18 - Prob. 18.56PCh. 18 - In certain ranges of a piano keyboard, more than...Ch. 18 - Prob. 18.58PCh. 18 - Review. A student holds a tuning fork oscillating...Ch. 18 - An A-major chord consists of the notes called A,...Ch. 18 - Suppose a flutist plays a 523-Hz C note with first...Ch. 18 - A pipe open at both ends has a fundamental...Ch. 18 - Prob. 18.63APCh. 18 - Two strings are vibrating at the same frequency of...Ch. 18 - Prob. 18.65APCh. 18 - A 2.00-m-long wire having a mass of 0.100 kg is...Ch. 18 - The fret closest to the bridge on a guitar is 21.4...Ch. 18 - Prob. 18.68APCh. 18 - A quartz watch contains a crystal oscillator in...Ch. 18 - Review. For the arrangement shown in Figure...Ch. 18 - Prob. 18.71APCh. 18 - Two speakers are driven by the same oscillator of...Ch. 18 - Review. Consider the apparatus shown in Figure...Ch. 18 - Review. The top end of a yo-yo string is held...Ch. 18 - On a marimba (Fig. P18.75), the wooden bar that...Ch. 18 - A nylon siring has mass 5.50 g and length L = 86.0...Ch. 18 - Two train whistles have identical frequencies of...Ch. 18 - Review. A loudspeaker at the front of a room and...Ch. 18 - Prob. 18.79APCh. 18 - Prob. 18.80APCh. 18 - Prob. 18.81APCh. 18 - A standing wave is set up in a string of variable...Ch. 18 - Two waves are described by the wave functions...Ch. 18 - Prob. 18.84APCh. 18 - Review. A 12.0-kg object hangs in equilibrium from...Ch. 18 - Review. An object of mass m hangs in equilibrium...Ch. 18 - Review. Consider the apparatus shown in Figure...Ch. 18 - Prob. 18.88CP
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