Quantitative Chemical Analysis
Quantitative Chemical Analysis
9th Edition
ISBN: 9781464135385
Author: Daniel C. Harris
Publisher: W. H. Freeman
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Concept explainers

Question
Chapter 18, Problem 18.AE

(a)

Interpretation Introduction

Interpretation:

For the given transmittance value, the value of absorbance has to be calculated.

Concept introduction:

Beer-lambert law:

A=-logPPo=εcbwhere,A-absorbancePo-incidentirradianceandP-transmittedirradianceε-molarabsorptivityc-concentrationandb-pathlength.

(a)

Expert Solution
Check Mark

Answer to Problem 18.AE

The value of absorbance (A) is 0.347.

Explanation of Solution

Given information:

Transmittance=45.0%.

Apply the Beer’s law to calculate the value of absorbance (A)

A=-logPPo=-logT=-log(0.45)=0.347

The value of absorbance (A) is 0.347.

(b)

Interpretation Introduction

Interpretation:

The value of percent transmittance for 0.0200M solution has to be calculated.

Concept introduction:

Beer-lambert law:

A=-logPPo=εcbwhere,A-absorbancePo-incidentirradianceandP-transmittedirradianceε-molarabsorptivityc-concentrationandb-pathlength.

(b)

Expert Solution
Check Mark

Answer to Problem 18.AE

The value of percent transmittance for 0.0200M solution is 20.2%.

Explanation of Solution

Given information:

0.0100Msolutionexihibits45.0%T.Absorbance(A)=0.347For0.0200Msolution%T=?

Absorbance (A) is proportional to concentration (C) , here concentration is doubled so the value of A is doubled.

A=-logTT=10-A=10-0.694=0.202%T=20.2%.

The value of percent transmittance for 0.0200M solution is 20.2%.

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