Whether the reason for describing the reddish H II region as red hot is the same that for the filament of an electric toaster.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 18, Problem 1CC

To determine

Whether the reason for describing the reddish H II region as red hot is the same that for the filament of an electric toaster.

Expert Solution & Answer

Answer to Problem 1CC

Solution:

The filament of an electric toaster is blackbody that is why it glows whereas the reason for the reddish H II region is the emitted light due to the transition from n=3 to n=2.

Explanation of Solution

Introduction:

The notation used by the astronomers for the neutral hydrogen atoms that are not ionized is H I and for the hydrogen atoms that are ionized is H II. The emission nebulae primarily consists of hydrogen atoms that are ionized, meaning free protons and free electrons.

Explanation:

A nearby hot star emits high energy ultra-violet photons which are absorbed by the hydrogen atoms in the nebulae. These hydrogen atoms gain energy to get ionized into electrons and protons. These free protons and free electrons recombine to form hydrogen atoms through a process known as recombination. When the hydrogen atom forms by recombination, the electron is usually captured in a large, energetic orbit of the proton. This electron makes a transition to successive lower energy orbits. With each transition, a photon is emitted and each of these photons are less energetic and have a longer wavelength than that compared to the photons emitted from a hot star initially. Among all of the transitions, the important transition is from n=3 to n=2 which results in Hα photons which lies in the red region of the visible spectrum, that is, with a wavelength of 656 nm.

The black bodies absorb the entire radiation incident on it and emit some other light carrying enough energy to maintain a particular equilibrium temperature. This implies every hot object glows by emitting the radiation. The filament of the electric toaster is also hot black bodies. This is the reason for the red glow of the electric toaster filament.

Conclusion:

The reddish H II region appears because of the emitted light in the red region of the visible spectrum.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

At what wavelengths do stars of surface temperates 20 000 K, 10 000 K, and 3000 K have their peak intensity?

Answer 2

Question

Chapter 18, Problem 1CC

To determine

Whether the reason for describing the reddish H II region as red hot is the same that for the filament of an electric toaster.

Expert Solution & Answer

Answer to Problem 1CC

Solution:

The filament of an electric toaster is blackbody that is why it glows whereas the reason for the reddish H II region is the emitted light due to the transition from n=3 to n=2.

Explanation of Solution

Introduction:

The notation used by the astronomers for the neutral hydrogen atoms that are not ionized is H I and for the hydrogen atoms that are ionized is H II. The emission nebulae primarily consists of hydrogen atoms that are ionized, meaning free protons and free electrons.

Explanation:

A nearby hot star emits high energy ultra-violet photons which are absorbed by the hydrogen atoms in the nebulae. These hydrogen atoms gain energy to get ionized into electrons and protons. These free protons and free electrons recombine to form hydrogen atoms through a process known as recombination. When the hydrogen atom forms by recombination, the electron is usually captured in a large, energetic orbit of the proton. This electron makes a transition to successive lower energy orbits. With each transition, a photon is emitted and each of these photons are less energetic and have a longer wavelength than that compared to the photons emitted from a hot star initially. Among all of the transitions, the important transition is from n=3 to n=2 which results in Hα photons which lies in the red region of the visible spectrum, that is, with a wavelength of 656 nm.

The black bodies absorb the entire radiation incident on it and emit some other light carrying enough energy to maintain a particular equilibrium temperature. This implies every hot object glows by emitting the radiation. The filament of the electric toaster is also hot black bodies. This is the reason for the red glow of the electric toaster filament.

Conclusion:

The reddish H II region appears because of the emitted light in the red region of the visible spectrum.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 18, Problem 1CC

To determine

Whether the reason for describing the reddish H II region as red hot is the same that for the filament of an electric toaster.

Expert Solution & Answer

Answer to Problem 1CC

Solution:

The filament of an electric toaster is blackbody that is why it glows whereas the reason for the reddish H II region is the emitted light due to the transition from n=3 to n=2.

Explanation of Solution

Introduction:

The notation used by the astronomers for the neutral hydrogen atoms that are not ionized is H I and for the hydrogen atoms that are ionized is H II. The emission nebulae primarily consists of hydrogen atoms that are ionized, meaning free protons and free electrons.

Explanation:

A nearby hot star emits high energy ultra-violet photons which are absorbed by the hydrogen atoms in the nebulae. These hydrogen atoms gain energy to get ionized into electrons and protons. These free protons and free electrons recombine to form hydrogen atoms through a process known as recombination. When the hydrogen atom forms by recombination, the electron is usually captured in a large, energetic orbit of the proton. This electron makes a transition to successive lower energy orbits. With each transition, a photon is emitted and each of these photons are less energetic and have a longer wavelength than that compared to the photons emitted from a hot star initially. Among all of the transitions, the important transition is from n=3 to n=2 which results in Hα photons which lies in the red region of the visible spectrum, that is, with a wavelength of 656 nm.

The black bodies absorb the entire radiation incident on it and emit some other light carrying enough energy to maintain a particular equilibrium temperature. This implies every hot object glows by emitting the radiation. The filament of the electric toaster is also hot black bodies. This is the reason for the red glow of the electric toaster filament.

Conclusion:

The reddish H II region appears because of the emitted light in the red region of the visible spectrum.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 18, Problem 1CC

To determine

Whether the reason for describing the reddish H II region as red hot is the same that for the filament of an electric toaster.

Expert Solution & Answer

Answer to Problem 1CC

Solution:

The filament of an electric toaster is blackbody that is why it glows whereas the reason for the reddish H II region is the emitted light due to the transition from n=3 to n=2.

Explanation of Solution

Introduction:

The notation used by the astronomers for the neutral hydrogen atoms that are not ionized is H I and for the hydrogen atoms that are ionized is H II. The emission nebulae primarily consists of hydrogen atoms that are ionized, meaning free protons and free electrons.

Explanation:

A nearby hot star emits high energy ultra-violet photons which are absorbed by the hydrogen atoms in the nebulae. These hydrogen atoms gain energy to get ionized into electrons and protons. These free protons and free electrons recombine to form hydrogen atoms through a process known as recombination. When the hydrogen atom forms by recombination, the electron is usually captured in a large, energetic orbit of the proton. This electron makes a transition to successive lower energy orbits. With each transition, a photon is emitted and each of these photons are less energetic and have a longer wavelength than that compared to the photons emitted from a hot star initially. Among all of the transitions, the important transition is from n=3 to n=2 which results in Hα photons which lies in the red region of the visible spectrum, that is, with a wavelength of 656 nm.

The black bodies absorb the entire radiation incident on it and emit some other light carrying enough energy to maintain a particular equilibrium temperature. This implies every hot object glows by emitting the radiation. The filament of the electric toaster is also hot black bodies. This is the reason for the red glow of the electric toaster filament.

Conclusion:

The reddish H II region appears because of the emitted light in the red region of the visible spectrum.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 18, Problem 1CC

To determine

Whether the reason for describing the reddish H II region as red hot is the same that for the filament of an electric toaster.

Expert Solution & Answer

Answer to Problem 1CC

Solution:

The filament of an electric toaster is blackbody that is why it glows whereas the reason for the reddish H II region is the emitted light due to the transition from n=3 to n=2.

Explanation of Solution

Introduction:

The notation used by the astronomers for the neutral hydrogen atoms that are not ionized is H I and for the hydrogen atoms that are ionized is H II. The emission nebulae primarily consists of hydrogen atoms that are ionized, meaning free protons and free electrons.

Explanation:

A nearby hot star emits high energy ultra-violet photons which are absorbed by the hydrogen atoms in the nebulae. These hydrogen atoms gain energy to get ionized into electrons and protons. These free protons and free electrons recombine to form hydrogen atoms through a process known as recombination. When the hydrogen atom forms by recombination, the electron is usually captured in a large, energetic orbit of the proton. This electron makes a transition to successive lower energy orbits. With each transition, a photon is emitted and each of these photons are less energetic and have a longer wavelength than that compared to the photons emitted from a hot star initially. Among all of the transitions, the important transition is from n=3 to n=2 which results in Hα photons which lies in the red region of the visible spectrum, that is, with a wavelength of 656 nm.

The black bodies absorb the entire radiation incident on it and emit some other light carrying enough energy to maintain a particular equilibrium temperature. This implies every hot object glows by emitting the radiation. The filament of the electric toaster is also hot black bodies. This is the reason for the red glow of the electric toaster filament.

Conclusion:

The reddish H II region appears because of the emitted light in the red region of the visible spectrum.

Answer 6

Chapter 18, Problem 1CC

To determine

Whether the reason for describing the reddish H II region as red hot is the same that for the filament of an electric toaster.

Expert Solution & Answer

Answer to Problem 1CC

Solution:

The filament of an electric toaster is blackbody that is why it glows whereas the reason for the reddish H II region is the emitted light due to the transition from n=3 to n=2.

Explanation of Solution

Introduction:

The notation used by the astronomers for the neutral hydrogen atoms that are not ionized is H I and for the hydrogen atoms that are ionized is H II. The emission nebulae primarily consists of hydrogen atoms that are ionized, meaning free protons and free electrons.

Explanation:

A nearby hot star emits high energy ultra-violet photons which are absorbed by the hydrogen atoms in the nebulae. These hydrogen atoms gain energy to get ionized into electrons and protons. These free protons and free electrons recombine to form hydrogen atoms through a process known as recombination. When the hydrogen atom forms by recombination, the electron is usually captured in a large, energetic orbit of the proton. This electron makes a transition to successive lower energy orbits. With each transition, a photon is emitted and each of these photons are less energetic and have a longer wavelength than that compared to the photons emitted from a hot star initially. Among all of the transitions, the important transition is from n=3 to n=2 which results in Hα photons which lies in the red region of the visible spectrum, that is, with a wavelength of 656 nm.

The black bodies absorb the entire radiation incident on it and emit some other light carrying enough energy to maintain a particular equilibrium temperature. This implies every hot object glows by emitting the radiation. The filament of the electric toaster is also hot black bodies. This is the reason for the red glow of the electric toaster filament.

Conclusion:

The reddish H II region appears because of the emitted light in the red region of the visible spectrum.

Answer 7

Chapter 18, Problem 1CC

To determine

Whether the reason for describing the reddish H II region as red hot is the same that for the filament of an electric toaster.

Answer 8

Expert Solution & Answer

Answer to Problem 1CC

Solution:

The filament of an electric toaster is blackbody that is why it glows whereas the reason for the reddish H II region is the emitted light due to the transition from n=3 to n=2.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Introduction:

The notation used by the astronomers for the neutral hydrogen atoms that are not ionized is H I and for the hydrogen atoms that are ionized is H II. The emission nebulae primarily consists of hydrogen atoms that are ionized, meaning free protons and free electrons.

Explanation:

A nearby hot star emits high energy ultra-violet photons which are absorbed by the hydrogen atoms in the nebulae. These hydrogen atoms gain energy to get ionized into electrons and protons. These free protons and free electrons recombine to form hydrogen atoms through a process known as recombination. When the hydrogen atom forms by recombination, the electron is usually captured in a large, energetic orbit of the proton. This electron makes a transition to successive lower energy orbits. With each transition, a photon is emitted and each of these photons are less energetic and have a longer wavelength than that compared to the photons emitted from a hot star initially. Among all of the transitions, the important transition is from n=3 to n=2 which results in Hα photons which lies in the red region of the visible spectrum, that is, with a wavelength of 656 nm.

The black bodies absorb the entire radiation incident on it and emit some other light carrying enough energy to maintain a particular equilibrium temperature. This implies every hot object glows by emitting the radiation. The filament of the electric toaster is also hot black bodies. This is the reason for the red glow of the electric toaster filament.

Conclusion:

The reddish H II region appears because of the emitted light in the red region of the visible spectrum.