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Chapter 18, Problem 1SAQ
Interpretation Introduction

Interpretation: The correct coefficients for each reactant and product are to be chosen for the following reaction from the given options:

_VO2+(aq)+__Sn(s)+__H +(aq) __VO2+(aq)+__Sn2+(aq)+__H2O(l)

a) 2, 1, 4 → 2, 1, 2

b) 1, 1, 2 → 1, 1, 1

c) 2, 1, 2 → 2, 1, 1

d) 2, 1, 2 → 2, 1, 2

Expert Solution & Answer
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Answer to Problem 1SAQ

Solution:

To solve this problem, begin by assigning oxidation states to all atoms and identify the substances being oxidized and reduced.

Explanation of Solution

The equation for this reaction as follows:

VO2+(aq)+Sn(s)+H+(aq)VO2+(aq)+Sn2+(aq)+H2O(l)

Modified Mastering Chemistry with Pearson eText -- ValuePack Access Card -- for Chemistry: A Molecular Approach (3rd Edition), Chapter 18, Problem 1SAQ

Separate the overall reaction into two half-reactions: one for oxidation and other for reduction.

Oxidation:Sn(s)Sn2+(aq)Reduction:VO2+(aq)VO2+(aq)

Balance each half-reaction; balance O by adding H2O and balance H by adding H+.

Sn(s)Sn2+(aq)VO2+(aq)VO2+(aq)+H2O(l)2H+(aq)+VO2+(aq)VO2+(aq)+H2O(l)

Balance each-half reaction with respect to charge by adding electrons. Make the sum of the charges on both sides of the equation equal by adding as many electrons as necessary.

Sn(s)Sn2+(aq)+2e2H+(aq)+VO2+(aq)+eVO2+(aq)+H2O(l)

Make the number of electrons in both-half reactions equal by multiplying one or both half-reactions by a small whole number.

Sn(s)Sn2+(aq)+2e2[2H+(aq)+VO2+(aq)+eVO2+(aq)+H2O(l)]4H+(aq)+2VO2+(aq)+2e2VO2+(aq)+2H2O(l)

Add the two half-reaction together, cancelling electrons and other species as necessary.

Sn(s)Sn2+(aq)+2e4H+(aq)+2VO2+(aq)+2eVO2+(aq)+2H2O(l)2VO2+(aq)+Sn(s)+4H+(aq)2VO2+(aq)+Sn2+(aq)+2H2O(l)

Conclusion:

Thus, the coefficient of each reactant and product will be 2,1,42,1,2 and the correct answer will be option (a).

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Chapter 18 Solutions

Modified Mastering Chemistry with Pearson eText -- ValuePack Access Card -- for Chemistry: A Molecular Approach (3rd Edition)

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