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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

Using Kirchhoff’s rules (a) find the current in each resistor shown in Figure P18.25 and (b) find the potential difference between point c and f.

images

Figure P18.25

(a)

To determine
The current in each resistor I1,I2,I3

Explanation

Given Info:

Resistance R1 is 2.00 , Resistance R2 is 3.00 , Resistance R3 is 4.00 , Voltage ε1 is 70.0V , Voltage ε2 is 60.0V , and Voltage ε3 is 80.0V .

Explanation:

The below figure shows the direction of current flow in the circuit.

  • ε1,ε2,ε3 is voltage in the circuits
  • R1,R2,R3 is corresponding resistance in the circuits
  • I1,I2,I3 is corresponding current in the circuits

Apply Kirchhoff’s voltage law to the left and right loop.

From the left loop abcfa,

ε1ε2R1I1R2I2=0

Substitute, 2.00 for R1 , 3.00 for R2 , 70.0V for ε1 and 60.0V for ε2 , in the above equation to find expression for abcfa

70.0V60.0V(2.00)I1(3.00)I2=010.0V(3.00)I2=2.00I15.0V(1.50)I2=I1 (I)

From the right loop edcfe,

ε3ε2R2I2R3I3=0

Substitute, 3.0 for R2 , 4.0 for R3 60.0V for ε2 and 80.0V for ε3 in the above equation to find expression for edcfe,

80.0V60.0V4.00I33.00I2=020.0V4.00I33.00I2=020.0V3.00I2=4.00I35.0V0.75I2=I3 (II)

Conclusion:

Formula to calculate current by using Kirchhoff’s junction rule

I2=I1+I3

Use, 5

(b)

To determine
The potential difference between point c and f.

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