Chapter 18, Problem 26P

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Chapter
Section

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# Figure P18.26 shows a voltage divider, a circuit used to obtain a desired voltage ΔVout from a source voltage ε. Determine the required value of R2 if ε = 5.00 V, ΔVout = 1.50 V and R1 = 1.00 × 103 Ω (Hint: Use Kirchhoff's loop rule, substituting ΔVout = IR2, to find the current. Then solve Ohm’s law for R2.Figure P18.26

To determine
The current I in the circuit and resistance R2 by using ohm’s law.

Explanation

Given Info: Source voltage Îµ is 5.00â€‰V , desired voltage Î”Vout is 1.50â€‰V Resistance R1 is 1.00Ã—103â€‰Î© , desired voltage in terms of I is Vout is IR2 .

Explanation:

Apply Kirchhoffâ€™s loop rule

Îµâˆ’IR1âˆ’Vout=0

On rearrange

Îµâˆ’IR1âˆ’Vout=0I=Îµâˆ’VoutR1

Formula to calculate the current I in the circuit is

I=Îµâˆ’VoutR1

• I is the current in the circuit
• Îµ is the source voltage
• R1 is the Resistance
• Vout is the desired voltage obtain from source voltage.

Substitute 5.00â€‰V for Îµ and 1.00Ã—103â€‰Î© for R1 and 1.50â€‰V for Î”Vout to find I

I=5

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