College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Chapter
Section

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

Find the potential difference across each resistor in Figure P18.31.Figure P18.31

To determine
The potential difference across in each resistor.

Explanation

Given Info:

Resistance R1 is 5.00â€‰Î© , Resistance R2 is 4.00â€‰Î© , Resistance R3 is 3.00â€‰Î© , Resistance R4 is 2.00â€‰Î© , The expression for I2 is 3.00â€‰Vâˆ’0.800â€‰Î©â€‰I3 , the expression for I1 is 1.80â€‰Vâˆ’0.800â€‰Î©â€‰I3 , the current in the circuits I1 is 0.324â€‰A , I3 is 1.846â€‰A , I2 is 1.524â€‰A , Resistance R1 is 5.00â€‰Î© , Resistance R2 is 4.00â€‰Î© , Resistance R3 is 3.00â€‰Î© , Resistance R4 is 2.00â€‰Î© .

Explanation:

Voltage Îµ1 is 12.0â€‰V , Voltage Îµ2 is 3.00â€‰V , Voltage Îµ3 is 18.0â€‰V

The below figure shows the direction of current flow in the circuit.

• Îµ1,Îµ2,Îµ3 is voltage in the circuits
• R1,R2,R3,R4 is corresponding resistance in the circuits
• I1,I2,I3 is corresponding current in the circuits

Formula to calculate the expression for current by Kirchhoffâ€™s voltage law

From the Left loop

Îµ1âˆ’Îµ2âˆ’R1I1âˆ’R2I3=0

Substitute 5.00â€‰Î© for R1 , 4.00â€‰Î© for R2 , 3.00â€‰V for Îµ2 12.0â€‰V for Îµ1 in the above equation to find expression for I1

From the right loop

Îµ3âˆ’Îµ2âˆ’R2I3âˆ’(R3+R4)I2=0

Substitute 4.00â€‰Î© for R2 , 3.00â€‰Î© for R3 , 2.00â€‰Î© for R4 , 12.0â€‰V for Îµ2 , 18.0â€‰V for Îµ3 in the above equation to find expression for I1

Conclusion:

Thus, from the Left loop the expression I1 is 1.80â€‰Vâˆ’0.800â€‰Î©â€‰I3 and from the right loop the expression I2 is 3

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