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6th Edition

Stewart + 5 others

Publisher: Cengage Learning

ISBN: 9780840068071

Chapter 1.8, Problem 39E

(a)

To determine

**To verify:** The triangle

Expert Solution

**Given information:**

The figure,

**Formula used:**

Converse of Pythagoras theorem states that if the sum of squares of two sides of a triangle is equal to the square of longest side of the triangle, then the triangle is a right triangle.

Distance formula between two points

**Proof:**

Consider the given figure,

In the above figure, the coordinates of the vertices of the triangle ABC are

Recall that the distance formula between two points

So, length of AB will be calculated as.

Now, the length of BC will be calculated as,

Length of AC will be calculated s,

Now, calculate the sum of squares of AB and BC as,

Recall the converse of Pythagoras theorem if the sum of squares of two sides of a triangle is equal to the square of longest side of the triangle, then the triangle is a right triangle.

Here, square of longest side i.e. AC is equal to the sum of squares of other two sides, i.e. AB and BC, so, the given triangle ABC is a right triangle.

Thus, using converse of Pythagoras theorem it is proved that the triangle ABC is a right triangle.

(b)

To determine

To calculate: The area of triangle ABC.

Expert Solution

The area of triangle ABC is

**Given information:**

The figure,

**Formula used:**

Area of a triangle is half into the product of its base and height. So, if b is the base and h is the height of the triangle, then area of triangle is expressed as,

**Calculation:**

Consider the given figure,

In (a) part, lengths of sides of triangle are calculated as,

Length of AB

Length of BC

Length of AC

Since, AC is longest, so, it is hypotenuse and AB is shortest, so, AB is the perpendicular (height) and BC is base of the triangle.

Recall area of a triangle is half into the product of its base and height. So, if b is the base and h is the height of the triangle, then area of triangle is expressed as,

Apply it,

Simplify it further as,

Thus, area of the triangle ABC is