Chapter 18, Problem 39P

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

Chapter
Section

### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

# What minimum number of 75-W light bulbs must be connected in parallel to a single 120-V household circuit to trip a 30.0-A circuit breaker?

To determine

To determine The number of light bulbs needed to trip a 30.0A circuit breaker

Explanation

Given Info: Output Power PÂ  drawn by single bulb is 75â€‰W , Output Voltage V is 120â€‰V

Explanation:

Formula to calculate the current is,

PÂ =Â IOneÂ bulbâ€‰VÂ

On Rearranging

IOneÂ bulb=PV

• P is the Electric Power
• IOneÂ bulb is the current in one bulb
• V is the supplied voltage

Substitute 75â€‰W for P and 120â€‰V for V to find IOneÂ bulb .

IOneÂ bulb=75â€‰W120â€‰VÂ Â Â Â Â Â Â Â Â Â Â ï¿½

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