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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

Figure P18.49 shows separate series and parallel circuits. (a) What is the ratio ΔVseriesVparallel? (b) What is the ratio of the power dissipated by the resistors in the series to the parallel circuit, Pseries/Pparallel?

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Figure P18.49

(a)

To determine
The total power delivered to the three bulbs shown in the figure.

Explanation

Given Info: The power of the three light bulbs is 60.0W and potential developed across the power source is 120V . The resistors R2 and R3 is in series with resistor R1 is 240Ω .

Explanation:

Formula to calculate the resistors of each of the three bulbs is,

P=(ΔV)2R

  • P is the power of the light bulbs,
  • ΔV is the potential difference across the power source,
  • R is the resistor,

Rewrite the expression in terms of R.

R=(ΔV)2P

Substitute 120V for ΔV and 60.0W for P .

R=(120V)2(60.0W)=240Ω

Thus, the resistors of each of the three bulbs is 240Ω .

The equivalent resistance of the circuit connected in the parallel combination of R2 and R3 is in series with R1 is,

Requ=R1+(1R2+1R3)1

(b)

To determine
The potential difference across each resistor of the bulb.

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