   Chapter 18, Problem 51AP

Chapter
Section
Textbook Problem

When two unknown resistors are connected in series with a battery, the battery delivers 225 W and carries a total current of 5.00 A. For the same total current, 50.0 W is delivered when the resistors are connected in parallel. Determine the value of each resistor.

(a)

To determine
The current in 5.00Ω resistor.

Explanation

Formula to calculate the current in 5.00Ω resistor is,

I5=ΔVpR5

• ΔVp is the potential difference in the parallel combination.
• R5 is the 5.00Ω resistance.

Formula to calculate the potential difference in the parallel combination is,

ΔVp=IRp

• I is the total current in the circuit.
• Rp is the equivalent resistance of the parallel combination.

The equivalent resistance of the parallel combination is,

Rp=(5.00Ω)(8.00Ω)(5.00Ω)+(8.00Ω)=3.08Ω

The total current is given by,

I=εRp+10

(b)

To determine
The power delivered to the 5.00Ω resistor.

(c)

To determine
The circuit which requires Kirchhoff’s rules to find currents.

(d)

To determine
The circuit in which smallest amount of power is delivered to 10.0Ω resistor.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts 