# A chemist studied the reaction mechanism for the reaction 2 NO ( g ) + O 2 ( g ) → 2 NO 2 ( g ) by reacting N 16 O with 18 O 2 . If the reaction mechanism is NO + O 2 ⇌ NO 3 ( fast equilibrium ) NO 3 + NO → 2 NO 2 ( s l o w ) what distribution of 18 O would you expect in the NO 2 ? Assume that N is the central atom in NO 3 , assume only N 16 O 18 O 2 forms, and assume stoichiometric amounts of reactants are combined.

### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

Chapter
Section

### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 18, Problem 54E
Textbook Problem
127 views

## A chemist studied the reaction mechanism for the reaction 2 NO ( g )   +   O 2 ( g )   →   2 NO 2 ( g ) by reacting N16O with 18O2. If the reaction mechanism is NO   +   O 2 ⇌ NO 3 ( fast equilibrium ) NO 3   +   NO → 2 NO 2 ( s l o w ) what distribution of 18O would you expect in the NO2? Assume that N is the central atom in NO3, assume only N16O18O2 forms, and assume stoichiometric amounts of reactants are combined.

Interpretation Introduction

Interpretation: The reaction mechanism of the given reaction is given to be studied by a chemist. On the basis of given assumptions, the expected distribution of 18O in NO2 is to be stated.

Concept introduction: Chemical equilibrium is a state of a system in which the rate of forward and backward reactions is equal. It is affected by various factors such as concentration of reactants or products, temperature, pressure etc.

To determine: The expected distribution of 18O in NO2 .

### Explanation of Solution

Explanation

The reaction for which the reaction mechanism is studied is given below.

2NO(g)+O2(g)2NO2(g) (1)

This reaction is done by reacting N16O with 18O2 .

The given reaction mechanism is,

NO+O2NO3(fast equilibrium) (2)

NO3+NO2NO2(slow) (3)

The slow step is the rate determining step

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