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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

The resistor R in Figure P18.58 dissipates 20 W of power. Determine the value of R.

images

Figure P18.58

(a)

To determine
the graph of power dissipated in the load resistor as a function of the load resistance.

Explanation

Given Info:

Internal resistance of the battery is 10.0Ω .

The open circuit voltage of the battery is 12.0V .

The variable resistance connected across the battery is, 0 to 30.0Ω .

Explanation:

Thus, from the circuit; the current in the circuit is,

I=12.0VR+10.0Ω (I)

Formula to calculate the power delivered to the load resistor is,

PLoad=I2R (II)

  • I is the current in the circuit
  • R is the load resistor

Substitute equation (I) in (II),

PLoad=(144V2)R(R+10

(b)

To determine

To demonstrate: the theorem “The power delivered to a load is a maximum if the load resistance equals the internal resistance of the source”.

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