# The blank in the statement “To find thex-intercept(s) of the graph of the equation we set and solve for .The x-intercept for the equation 2 y = x + 1 is .”

BuyFind

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.8, Problem 5E

(a)

To determine

Expert Solution

## Answer to Problem 5E

The complete statement is “To find the x-intercept(s) of the graph of the equation we set y=0 and solve for x .The x-intercept for the equation 2y=x+1 is 1 .”

### Explanation of Solution

Given information:

The statement “To find the x-intercept(s) of the graph of the equation we set       and solve for         .The x-intercept for the equation 2y=x+1 is       .”

Consider the provided statement “To find the x-intercept(s) of the graph of the equation we set       and solve for         .The x-intercept for the equation 2y=x+1 is       .”

The x-intercepts are the points on x-axis where the graph of the equation intersects the x-axis.

Substitute y=0 in the equation 2y=x+1 ,

2(0)=x+10=x+1x=1

Therefore, x-intercept is 1 .

Thus, the complete statement is “To find the x-intercept(s) of the graph of the equation we set y=0 and solve for x .The x-intercept for the equation 2y=x+1 is 1 .”

(b)

To determine

Expert Solution

## Answer to Problem 5E

The complete statement is “To find the y-intercept(s) of the graph of the equation we set x=0 and solve for y .They-intercept for the equation 2y=x+1 is 12 .”

### Explanation of Solution

Given information:

The statement “To find the y-intercept(s) of the graph of the equation we set       and solve for         .They-intercept for the equation 2y=x+1 is       .”

Consider the provided statement “To find the y-intercept(s) of the graph of the equation we set       and solve for         . The y-intercept for the equation 2y=x+1 is       .”

The y-intercepts are the points on y-axis where the graph of the equation intersects the y-axis.

Substitute x=0 in the equation 2y=x+1 ,

2y=0+12y=1y=12

Therefore, x-intercept is 1 .

Thus, the complete statement is “To find the y-intercept(s) of the graph of the equation we set x=0 and solve for y . The y-intercept for the equation 2y=x+1 is 12 .”

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