   Chapter 18, Problem 66AP

Chapter
Section
Textbook Problem

Consider the two arrangements of batteries and bulbs shown in Figure P18.66. The two bulbs are identical and have resistance R, and the two batteries are identical with output voltage ΔV. (a) In case 1, with the two bulbs in series, compare the brightness of each bulb, the current in each bulb, and the power delivered to each bulb. (b) In case 2, with the two bulbs in parallel, compare the brightness of each bulb, the current in each bulb, and the power supplied to each bulb. (c) Which bulbs are brighter, those in case 1 or those in case 2? (d) In each case, if one bulb fails, will the other go out as well? If the other bulb doesn’t fail, will it get brighter or stay the same? (Problem 66 is courtesy of E. F. Redish. For other problems of this type, visit http://www.physics.umd.edu/perg/.) Figure P18.66

(a)

To determine
The value of the resistance R.

Explanation

Given Info: The potential reading in the voltmeter is 6.0V and current reading in the ammeter is 3.0mA .

Explanation:

Formula to calculate the value of the resistance R

R=ΔVI

• R is the resistance,
• ΔV is the voltmeter reading,
• I is the ammeter reading,

Substitute 6.0V for ΔV and 3.0mA for I .

R=(6

(b)

To determine
The emf of the battery.

(c)

To determine
The voltage across the 3.0kΩ resistor.

(d)

To determine
The assumption make to solve the problem.

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