The value of K p for the following reaction at 425 °C is 0.018. What is the value of Δ r G °at this temperature? 2 HI(g) ⇄ H 2 (g) + I 2 (g) (a) 1.0 × 10 1 kJ/md-rxn (b) −14 kJ/mol-rxn (c) 23 kJ/mol-rxn (d) 240 kJ/mol-rxn

Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

Chapter
Section

Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 18.7, Problem 3RC
Textbook Problem
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The value of Kp for the following reaction at 425 °C is 0.018. What is the value of ΔrG°at this temperature?2 HI(g)  ⇄ H2(g) + I2(g) (a) 1.0 × 101 kJ/md-rxn (b) −14 kJ/mol-rxn (c) 23 kJ/mol-rxn (d) 240 kJ/mol-rxn

Interpretation Introduction

Interpretation: the value of ΔrG will be identified by using values of ΔfG in the reaction from the given options.

Concept introduction:

The relation between ΔrG and Kp is,

ΔrG=RTlnKp Ttemperature Runiversalgasconstant

Explanation of Solution

For the given reaction,

Kp is 0.018 .

T is 425C=(425+273)K=698K

R is 8.3145J/Kmol

The relation between ΔrG and Kp is,

ΔrG=RTlnKp

Therefore,

ΔrG=RTlnKp =(8.3145J/Kmol×698K×ln(0

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