   Chapter 19, Problem 12P

Chapter
Section
Textbook Problem

A proton travels with a speed of 5.02 × 106 m/s at an angle of 60° with the direction of a magnetic field of magnitude 0.180 T in the positive x-direction. What are (a) the magnitude of the magnetic force on the proton and (b) the proton’s acceleration?

a)

To determine
The magnitude of the magnetic force on the proton.

Explanation

Given info: The speed of the proton is 5.02×106ms-1 . The magnitude of the magnetic field is 0.180T . The direction of the magnetic field is along x-direction. The angle between the magnetic field and the velocity of the proton is 60° .

Explanation:

The magnetic force on a charged particle is given by,

F=qvBsinθ       (1)

• q is the charge on the particle
• v is the velocity of the particle
• B is the magnetic field
• θ is the angle between the velocity and the magnetic field

Substitute 1.60×1019C for q , 5.02×106ms-1 for v , 0

b)

To determine
The magnitude of the proton’s acceleration.

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