   Chapter 19, Problem 24PS

Chapter
Section
Textbook Problem

From the following list, identify those elements that are easier to oxidize than H2(g). (a) Cu (b) Zn (c) Fe (d) Ag (e) Cr

Interpretation Introduction

Interpretation:

The elements which are easier to oxidize compared to H2(g) have to be identified.

a)Cu        d)Agb)Zn        e)Crc)Fe

Concept introduction:

Under certain conditions a cell potential is measured it is called as standard potential (Ecello).

Standard potential (Ecello) can be calculated by the following formula.

Ecello=Ecathodeo-Eanodeo

The Ecello value is positive, the reaction is predicted to be product favoured at equilibrium.

The Ecello value is negative, the reaction is predicted to be reactant favoured at equilibrium.

Electrochemical series:

It is a decreasing order of the reduction potentials. The most positive E0 are placed in the top in the electrochemical series, it has greater tendency for reduction and lower tendency of oxidation. And the most negative E0 values of elements are placed in the bottom of the series.

Explanation

Reasons for correct answer:

Let’s write the E0 values of the given elements.

a) Cu2+(aq) + 2e- Cu(s) ;Eo= +0.337 Vb) Zn2+(aq) + 2e- Zn(s) ;E0= -0.763 Vc) Fe2+(aq) + 2e- Fe(s)  ;E0= -0.44 Vd) Ag+(aq) + e- Ag(s)   ;E0= +0.794 Ve) Cr3+(aq) + 2e- Cr(s)  ;E0= -0

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