BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.9, Problem 38E
To determine

To calculate: The value of x from the equation x2+3=2x by algebraic method and graphical method.

Expert Solution

Answer to Problem 38E

The value of x is none.

Explanation of Solution

Given information:

The equation x2+3=2x .

Calculation:

It is provided that the equation x2+3=2x .

Algebraic method;

The method in which isolate x on one side of the equation and solve the value of x .

From the equation x2+3=2x .

Subtract 2x on the both side of the equation,

  x2+32x=2x2xx2+32x=0

Apply quadratic formula and Solve the value of x ,

  x=(2)±(2)24132x=2±8i2

Therefore, the value of x=2±8i2 .

The value of x is not real so there is no solution.

Graphical method;

Let put y1=x2+3 and y2=2x

The graph of the equation y1=x2+3 provided below,

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.9, Problem 38E , additional homework tip  1

The graph of equation y2=2x is provided below,

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.9, Problem 38E , additional homework tip  2

The graph of both equations in same figure is provided below,

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.9, Problem 38E , additional homework tip  3

The solution is the x coordinate of the intersection point of the two graphs. The intersection point on the x coordinate is 0.

Thus, the value of x is 0.

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