BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.9, Problem 39E
To determine

To calculate: The value of x from the equation

  16x4=625 by algebraic method and graphical method.

Expert Solution

Answer to Problem 39E

The value of x is ±2.5 and the graph of the equation 16x4=625 provided below,

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.9, Problem 39E , additional homework tip  1

Explanation of Solution

Given information:

The equation 16x4=625 .

Calculation:

It is provided that the equation 16x4=625 .

Algebraic method;

The method in which isolate x on one side of the equation and solve the value of x .

From the equation 16x4=625 .

Divided by 16 on the both side of the equation,

  16x416=62516

Further solve for the value of x ,

  x4=62516x=6251614x=±52

Therefore, the value of x=±2.5 .

Graphical method;

Let put y1=16x4 and y2=625

The graph of the equation y1=16x4 provided below,

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.9, Problem 39E , additional homework tip  2

The graph of equation y2=625 is provided below,

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.9, Problem 39E , additional homework tip  3

The graph of both equations in same figure is provided below,

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.9, Problem 39E , additional homework tip  4

The solution is the x coordinate of the intersection point of the two graphs. The intersection point on the x coordinate is ±2.5 .

Thus, the value of x is ±2.5 .

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