BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.9, Problem 40E
To determine

To calculate: The value of x from the equation 2x5243=0 by algebraic method and graphical method.

Expert Solution

Answer to Problem 40E

The value of x is 2.611 and the graph of the equation 2x5243=0 provided below,

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.9, Problem 40E , additional homework tip  1

Explanation of Solution

Given information:

The equation 2x5243=0 .

Calculation:

It is provided that the equation 2x5243=0 .

Algebraic method;

The method in which isolate x on one side of the equation and solve the value of x .

From the equation 2x5243=0 .

Add 265 on the both side of the equation,

  2x5243+243=2432x5=243

Further solve for the value of x ,

  x5=2432x=243215x=2.611

Therefore, the value of x=2.611 .

Graphical method;

Let put y1=2x5 and y2=243

The graph of the equation y1=2x5 provided below,

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.9, Problem 40E , additional homework tip  2

The graph of equation y2=243 is provided below,

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.9, Problem 40E , additional homework tip  3

The graph of both equations in same figure is provided below,

  Precalculus: Mathematics for Calculus - 6th Edition, Chapter 1.9, Problem 40E , additional homework tip  4

The solution is the x coordinate of the intersection point of the two graphs. The intersection point on the x coordinate is 2.611 .

Thus, the value of x is 2.611 .

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