   Chapter 19, Problem 52P

Chapter
Section
Textbook Problem

GS A long, straight wire lies on a horizontal table in the xy-plane and carries a current of 1.20 μA in the positive x-direction along the x-axis. A proton is traveling in the negative x-direction at speed 2.30 × 104 m/s a distance d above the wire (i.e., z = d). (a) What is the direction of the magnetic field of the wire at the position of the proton? (b) What is the direction of the magnetic force acting on the proton? (c) Explain why the direction of the proton’s motion doesn’t change. (d) Using Newton’s second law, find a symbolic expression for d in terms of the acceleration of gravity g, the proton mass m, its speed v, charge q, and the current I. (e) Find the numeric answer for the distance d using the results of part (d).

(a)

To determine
The direction of the magnetic field of the wire at the position of the proton.

Explanation

Given Info: The wire is lying on a horizontal table in the xy-plane. The wire carries a current of 1.20μΑ and the current is flowing in the positive x-direction. The proton is travelling in the negative x-direction. The speed of the proton is 2.30×104ms-1 and it travels a distance d above the wire.

Explanation:

The direction of the magnetic field can be determined using the right hand rule 2

(b)

To determine
The direction of the magnetic force acting on the proton.

(c)

To determine
The reason why the direction of the proton’s motion does not change.

(d)

To determine
A symbolic expression for d in terms of acceleration due to gravity g , the proton mass m , the speed of the proton v , charge q , and the current I .

(e)

To determine
The numeric answer for the distance d .

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 