   Chapter 19, Problem 5P

Chapter
Section
Textbook Problem

A laboratory electromagnet produces a magnetic field of magnitude 1.50 T. A proton moves through this field with a speed of 6.00 × 106 m/s. (a) Find the magnitude of the maximum magnetic force that could be exerted on the proton. (b) What is the magnitude of the maximum acceleration of the proton? (c) Would the field exert the same magnetic force on an electron moving through the field with the same speed? (d) Would the electron undergo the same acceleration? Explain.

a)

To determine
The magnitude of the maximum magnetic force on the proton.

Explanation

Given info: The magnitude of the magnetic field is 1.50T . The speed of the proton is 6.00×106ms-1 .

Explanation:

The magnetic force on a charged particle is given by,

F=qvBsinθ       (1)

• q is the charge on the particle
• v is the velocity of the particle
• B is the magnetic field
• θ is the angle between the velocity and the magnetic field

The maximum force on the proton will be exerted when the velocity of the proton and the direction of the magnetic field are perpendicular to each other.

The maximum force will be,

Fm=qvBsin90°=qvB       (2)

Substitute 1.50T for B , 6.00×106ms-1 for v and 1

b)

To determine
The magnitude of maximum acceleration of the proton.

c)

To determine
Whether the field will exert the same force on an electron.

d)

To determine
Whether the electron undergoes same acceleration like proton.

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