   Chapter 19, Problem 62P

Chapter
Section
Textbook Problem

Certain experiments must be performed in the absence of any magnetic fields. Suppose such an experiment is located at the center of a large solenoid oriented so that a current of I = 1.00 A produces a magnetic field that exactly cancels Earth’s 3.50 × 10−5 T magnetic field. Find the solenoid’s number of turns per meter.

To determine
The number of turns of the solenoid.

Explanation

Given info: The current in the solenoid is 1.00A . The magnetic field inside the solenoid cancels the magnetic field of earth which is 3.50×105T .

Explanation:

The magnetic field inside a solenoid is given by,

B=μ0nI       (1)

• μ0 is the permeability of free space
• I is the current
• n is the number of turns per unit length

On re-arrangement,

n=Bμ0I

Since the field inside the solenoid cancels the magnetic field of earth, its magnitude must be same as the magnetic field of earth.

Substitute 4π×107TmA-1 for μ0 , 3

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