   Chapter 19, Problem 63P

Chapter
Section
Textbook Problem

Ail electron is moving at a speed of 1.0 × 104 in/s in a circular path of radius 2.0 cm inside a solenoid. The magnetic field of the solenoid is perpendicular to the plane of the electron’s path. Find (a) the strength of the magnetic field inside the solenoid and (b) the current in the solenoid if it has 25 turns per centimeter.

a)

To determine
The strength of the magnetic field inside the solenoid.

Explanation

Given info: The speed if a electron in a circular path of 2.0cm inside a solenoid is 1.0×104ms-1 .

Explanation:

Since the magnetic field supplies the centripetal acceleration,

qvB=mv2r

• B is the magnetic field present
• v is the velocity
• q is the charge of the particle
• r is the radius of the circular path
• m is the mass of the particle

Re-arranging for the magnetic field,

B=mvrq

Substitute 9.11×1031kg for m , 1.0×104ms-1 for v , 1.60×1019C for q , 2.0cm for r to determine the magnetic field,

B=(9.11×1031kg)(1

b)

To determine
The current inside the solenoid.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 