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ChemistryChemistry9th Edition

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Chapter 19, Problem 65AE
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Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

Solutions

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Problem 64AE
Problem 65AE
Problem 66AE
Problem 67AE
Problem 68AE
Problem 69AE
Problem 70AE
Problem 71AE
Problem 72AE
Problem 73CWP
Problem 74CWP
Problem 75CWP
Problem 76CWP
Problem 77CWP
Problem 78CWP
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Problem 84CP
Problem 85CP
Problem 86CP
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BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

During World War II, tritium (3H) was a component of fluorescent watch dials and hands. Assume you have such a watch that was made in January 1944. If 17% or more of the original tritium was needed to read the dial in dark places, until what year could you read the time at night? (For 3H, t1/2 = 12.3 yr.)

Interpretation Introduction

Interpretation: Use of tritium as a component of fluorescent watch dials and its half life is given. The year upto which the time at night can be read using the given kind of watch is to be calculated.

Concept introduction: A process through which an unstable nuclide looses its energy due to excess of protons or neutrons is known as radioactive decay. The cause of instability of a nuclide is its inefficiency in holding the nucleus together. Tritium was used as a component of fluorescent watch dials during world war 2

To determine: The year up to which the time at night can be read using the given kind of watch.

Explanation

Explanation

The decay constant is calculated by the formula given below.

λ=0.693t1/2

Where

  • t1/2 is the half life of nuclide.
  • λ is decay constant.

The value of t1/2 is 12.3 years .

Substitute the value of half life in the above formula.

λ=0.69312.3 year-1=0.05634 years-1_ .

The decay constant is 0.05634 year-1_

Explanation

Decay time is calculated by the formula,

t=2.303λlog(n0n)

Where

  • n0 is the number of atoms initially present.
  • n is the number of atoms remaining after decay.
  • t is the decay time.

Fraction of tritium remaining is 17n0100 .

Therefore, n=17n0100

Substitute the values of n , n0 and decay constant in the above equation.

t=2

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Ch-19 P-1RQCh-19 P-2RQCh-19 P-3RQCh-19 P-4RQCh-19 P-5RQCh-19 P-6RQCh-19 P-7RQCh-19 P-8RQCh-19 P-9RQCh-19 P-10RQ
Ch-19 P-1QCh-19 P-2QCh-19 P-3QCh-19 P-4QCh-19 P-5QCh-19 P-6QCh-19 P-7QCh-19 P-8QCh-19 P-9QCh-19 P-10QCh-19 P-11ECh-19 P-12ECh-19 P-13ECh-19 P-14ECh-19 P-15ECh-19 P-16ECh-19 P-17ECh-19 P-18ECh-19 P-19ECh-19 P-20ECh-19 P-21ECh-19 P-23ECh-19 P-24ECh-19 P-26ECh-19 P-27ECh-19 P-28ECh-19 P-29ECh-19 P-30ECh-19 P-31ECh-19 P-32ECh-19 P-33ECh-19 P-34ECh-19 P-35ECh-19 P-36ECh-19 P-37ECh-19 P-38ECh-19 P-39ECh-19 P-40ECh-19 P-41ECh-19 P-42ECh-19 P-43ECh-19 P-44ECh-19 P-46ECh-19 P-47ECh-19 P-48ECh-19 P-49ECh-19 P-50ECh-19 P-51ECh-19 P-52ECh-19 P-53ECh-19 P-54ECh-19 P-55ECh-19 P-56ECh-19 P-57ECh-19 P-58ECh-19 P-59AECh-19 P-60AECh-19 P-61AECh-19 P-62AECh-19 P-63AECh-19 P-64AECh-19 P-65AECh-19 P-66AECh-19 P-67AECh-19 P-68AECh-19 P-69AECh-19 P-70AECh-19 P-71AECh-19 P-72AECh-19 P-73CWPCh-19 P-74CWPCh-19 P-75CWPCh-19 P-76CWPCh-19 P-77CWPCh-19 P-78CWPCh-19 P-79CPCh-19 P-80CPCh-19 P-81CPCh-19 P-82CPCh-19 P-83CPCh-19 P-84CPCh-19 P-85CPCh-19 P-86CPCh-19 P-87IPCh-19 P-88IP

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