   # The simplest way to write the reaction for discharge in a lithium-ion battery is Li(on carbon)(s) + CoO 2 (s) → 6 C(s) + LiCoO 2 (s) (a) What are the oxidation numbers for cobalt in the two substances in the batter)? (b) In such a battery, what reaction occurs at the cathode? At the anode? (c) An electrolyte is needed for ion conduction within the battery. From what you know about lithium chemistry, can the electrolyte in the battery be dissolved in water? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 19, Problem 97GQ
Textbook Problem
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## The simplest way to write the reaction for discharge in a lithium-ion battery isLi(on carbon)(s) + CoO2(s) → 6 C(s) + LiCoO2(s) (a) What are the oxidation numbers for cobalt in the two substances in the batter)? (b) In such a battery, what reaction occurs at the cathode? At the anode? (c) An electrolyte is needed for ion conduction within the battery. From what you know about lithium chemistry, can the electrolyte in the battery be dissolved in water?

(a)

Interpretation Introduction

Interpretation: The oxidation numbers for cobalt in two substances in a lithium-ion battery has to be calculated.

Concept introduction: Oxidation number is also called oxidation state. The total number of electrons that an atom gain or loss to form a chemical bond with another atom is known as its oxidation state.

The loss of electrons is called oxidation whereas the gain of electrons is called reduction.

In an electrochemical cell, at anode oxidation takes place and at cathode reduction takes place.

### Explanation of Solution

The reaction for discharge in a lithium-ion battery is written as,

Li(s)+CoO2(s)6C(s)+LiCoO2(s)

There are two substances which are CoO2 and LiCoO2 where cobalt is present. The oxidation number for cobalt in these two substances is calculated as,

Each oxygen atom has an oxidation state of 2 because it can donate two electrons. Therefore, for two oxygen atoms, there is an oxidation state of 4. Suppose oxidation state on cobalt atom in CoO2 is x. So, the sum of oxidation state on each atom of CoO2 is zero is written as,

x+(2)(2)=

(b)

Interpretation Introduction

Interpretation:

The reaction at anode and cathode in a lithium-ion battery has to be stated.

Concept introduction: Oxidation number is also called oxidation state. The total number of electrons that an atom gain or loss to form a chemical bond with another atom is known as its oxidation state.

The loss of electrons is called oxidation whereas the gain of electrons is called reduction.

In an electrochemical cell, at anode oxidation takes place and at cathode reduction takes place.

(c)

Interpretation Introduction

Interpretation:

The lithium electrolyte in a battery can be dissolved in water has to be stated.

Concept introduction: Oxidation number is also called oxidation state. The total number of electrons that an atom gain or loss to form a chemical bond with another atom is known as its oxidation state.

The loss of electrons is called oxidation whereas the gain of electrons is called reduction.

In an electrochemical cell, at anode oxidation takes place and at cathode reduction takes place.

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