   # A lithium-ion camera battery is rated at 7500 mAh. That is, it can deliver 7500 milliamps (mA) or 7.5 amps of steady current for an hour. (a) How many moles of electrons can the battery deliver in one hour? (b) What mass of lithium is oxidized under these conditions in 1.0 hour? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 19, Problem 98GQ
Textbook Problem

## A lithium-ion camera battery is rated at 7500 mAh. That is, it can deliver 7500 milliamps (mA) or 7.5 amps of steady current for an hour. (a) How many moles of electrons can the battery deliver in one hour? (b) What mass of lithium is oxidized under these conditions in 1.0 hour?

(a)

Interpretation Introduction

Interpretation:

The number of moles of electrons a battery can deliver in one hour has to be determined.

Concept introduction:

The Faraday’s first law of electrolysis state that the mass of the substance (m) deposited at any electrode is directly proportional to the charge (Q) passed. The mathematical form of the Fraday’s first law is written as’

m=(QF)(MZ)

Here,

The symbol F is the Faraday’s constant.

The symbol M is the molar mass of the substance in grams per mol.

The symbol Z is the valency number of ions of the substance (electrons transferred per ion).

In the simple case of constant current electrolysis, Q=I×t leading to

m=(I×tF)(MZ) (1)

The above formula is written in terms of the number of moles (n),

n=(I×tF)(1Z) (2)

Here, t is the total time the constant current (I) is applied.

### Explanation of Solution

Given:

The constant current I=7.5A.

The time t is 3600s.

The faraday’s constant F is equal to 96500Cmol1.

The reaction of a lithium-ion battery is written as,

Li(s)LiCoO2(s)+e

Here, Z=1

(b)

Interpretation Introduction

Interpretation:

The mass of lithium oxidized under given conditions in one hour has to be calculated.

Concept introduction:

The Faraday’s first law of electrolysis state that the mass of the substance (m) deposited at any electrode is directly proportional to the charge (Q) passed. The mathematical form of the Fraday’s first law is written as’

m=(QF)(MZ)

Here,

The symbol F is the Faraday’s constant.

The symbol M is the molar mass of the substance in grams per mol.

The symbol Z is the valence number of ions of the substance (electrons transferred per ion).

In the simple case of constant current electrolysis, Q=I×t leading to

m=(I×tF)(MZ) (1)

The above formula is written in terms of the number of moles (n),

n=(I×tF)(1Z) (2)

Here, t is the total time the constant current (I) is applied.

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts
Imagine that you are standing in a pharmacy comparing the Supplement Facts panels on the labels of two suppleme...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

In a cylinder of an automobile engine, immediately after combustion the gas is confined to a volume of 50.0 cm3...

Physics for Scientists and Engineers, Technology Update (No access codes included)

Which elements are created in stellar nucleosynthesis?

Foundations of Astronomy (MindTap Course List) 