Chapter 19.4, Problem 16SC

Explanation of Solution

Applying “filter” before “map” method:

Stream <String> r = words.filter (w -> w.substring (0, 1).equalsIgnoreCase ("a")).map (w -> w.toLowerCase ());

• Here, “r” is a string stream variable.
• The “substring” method returns a string that is a substring of the given string. The “filter” method is used to pick out the substring of the given string that the user wants.
• The “equalsIgnoreCase” method returns true if the “a” is present in the given string.
• The “map” method yields a new stream with the transformed elements.

Applying “filter” after “map” method:

Stream <String> r = words...